#14 The personnel manager of a consumer product company asked a random sample ofemployees how they felt about the work they were doing. The following table gives a breakdown of the irresponses by gender. Do the data provide sufficient evidence to conclude that the level of job satisfactionis related to gender? Conduct the test at the 0.10 level of significance.ResponseFairlyInterestingGenderNotVeryInterestingInterestingMale70419Female353411Ho:Hi:Test statisticCritical Value =Conclusion:

The table shows the breakdown of their responses by gender.The hypothesis is, Null hypothesis: H0: The level of job satisfaction is not related to gender. Alternative hypothesis: H1: The level of job satisfaction is related to gender.The expected values are, Gender \ Response Very Interesting Fairly Interesting Not Interesting Total Male 120×105200=63 120×75200=45 120×20200=12 120 Female 80×105200=42 80×75200=30 80×20200=8 80 Total 105 75 20 200 The test statistic is, χ2=∑Observed-Expected2Expected=70-63263+41-45245+9-12212+35-42242+34-30230+11-828=0.778+0.356+0.750+1.167+0.533+1.125=4.707 Thus, the test statistic is 4.707.The degrees of freedom is, df=r-1c-1=2-13-1=2 The given level of significance is 0.10. The critical value of chi square distribution for 0.10 level of significance at 2 degrees of freedom can be obtained using the excel formula “=CHISQ.INV.RT(0.10, 2)”. The critical value is 4.605. Thus, the critical value is 4.605.Decision rule: If test statistic > critical value, then reject the null hypothesis. Conclusion: The test statistic (4.707) is greater than the critical value (4.605). Based on decision rule, reject the null hypothesis. Thus, there is enough evidence to conclude that the data provide sufficient evidence to conclude that the level of job satisfaction is related to gender.