The personnel director of Gadget Manufacturing Company has compiled the following table, which shows the percent of men and women employees who were absent the indicated number of days. Suppose there are as many women as men employees. Sex Absences (Days) Men Women 40% 20% 1-5 40% 20% 6-10 20% 40% 11 or more 0% 20% Total 100% 100% (a) Find the probability that an employee missed 6-10 days, given that the employee is a woman. (Enter your probability as a fraction.) (b) Find the probability that an employee is a woman, given that the employee missed 6-10 days. (Enter your probability as a fraction.)

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The personnel director of Gadget Manufacturing Company has compiled the following table, which shows the percent of men and women employees who were absent the indicated number of days. Suppose there
are as many women as men employees.
Sex
Absences (Days)
Men
Women
40%
20%
1-5
40%
20%
6-10
20%
40%
11 or more
0%
20%
Total
100%
100%
(a) Find the probability that an employee missed 6-10 days, given that the employee is a woman. (Enter your probability as a fraction.)
(b) Find the probability that an employee is a woman, given that the employee missed 6-10 days. (Enter your probability as a fraction.)
Transcribed Image Text:The personnel director of Gadget Manufacturing Company has compiled the following table, which shows the percent of men and women employees who were absent the indicated number of days. Suppose there are as many women as men employees. Sex Absences (Days) Men Women 40% 20% 1-5 40% 20% 6-10 20% 40% 11 or more 0% 20% Total 100% 100% (a) Find the probability that an employee missed 6-10 days, given that the employee is a woman. (Enter your probability as a fraction.) (b) Find the probability that an employee is a woman, given that the employee missed 6-10 days. (Enter your probability as a fraction.)
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