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The permanent magnet in Figure 1 is made of alnico 5, whose maximum energy product (-BmHm) is 40 kJ/m³. A flux density of Bg = 0.8 T is to be established in the air gap. The air gap has the dimensions A,= 2.5 cm² and l,= 0.4 cm. (a) Determine the minimum volume of the permanent magnet to produce the necessary air gap flux density. (b) Repeat part (a) if the permanent magnet is NdFeB (Neodymium-Iron-Boron), whose maximum energy product is 295 kJ/m³. (c) Calculate the reduction of the permanent magnet volume (the ratio of the NdFeB volume to the alnico 5 volume) required to produce the same flux density in the air gap by replacing alnico 5 with NdFeB. Assumption: The magnetic reluctance of soft iron is negligible, and the permeability of free space is µo = 4-7T-10-7 H/m.

The permanent magnet in Figure 1 is made of alnico 5, whose maximum energy product (-BmHm) is 40 kJ/m³. A flux density of Bg = 0.8 T is to be established in the air gap. The air gap has the dimensions A,= 2.5 cm² and l,= 0.4 cm. (a) Determine the minimum volume of the permanent magnet to produce the necessary air gap flux density. (b) Repeat part (a) if the permanent magnet is NdFeB (Neodymium-Iron-Boron), whose maximum energy product is 295 kJ/m³. (c) Calculate the reduction of the permanent magnet volume (the ratio of the NdFeB volume to the alnico 5 volume) required to produce the same flux density in the air gap by replacing alnico 5 with NdFeB. Assumption: The magnetic reluctance of soft iron is negligible, and the permeability of free space is µo = 4-7T-10-7 H/m.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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The permanent magnet in Figure 1 is made of alnico 5, whose maximum energy product (-BmHm) is 40 kJ/m³. A flux density of B, = 0.8 T is to be established in the air gap. The air gap has the dimensions A,= 2.5 cm² and l,= 0.4 cm. (a) Determine the minimum volume of the permanent magnet to produce the necessary air gap flux density. (b) Repeat part (a) if the permanent magnet is NdFeB (Neodymium-Iron-Boron), whose maximum energy product is 295 kJ/m³. (c) Calculate the reduction of the permanent magnet volume (the ratio of the NdFeB volume to the alnico 5 volume) required to produce the same flux density in the air gap by replacing alnico 5 with NdFeB. Assumption: The magnetic reluctance of soft iron is negligible, and the permeability of free space is µo = 4-T-10-7 H/m.
Transcribed Image Text:The permanent magnet in Figure 1 is made of alnico 5, whose maximum energy product (-BmHm) is 40 kJ/m³. A flux density of B, = 0.8 T is to be established in the air gap. The air gap has the dimensions A,= 2.5 cm² and l,= 0.4 cm. (a) Determine the minimum volume of the permanent magnet to produce the necessary air gap flux density. (b) Repeat part (a) if the permanent magnet is NdFeB (Neodymium-Iron-Boron), whose maximum energy product is 295 kJ/m³. (c) Calculate the reduction of the permanent magnet volume (the ratio of the NdFeB volume to the alnico 5 volume) required to produce the same flux density in the air gap by replacing alnico 5 with NdFeB. Assumption: The magnetic reluctance of soft iron is negligible, and the permeability of free space is µo = 4-T-10-7 H/m.
Soft iron Permanent magnet & (air gap) Ag Am Figure 1. Permanent magnet system. e
Transcribed Image Text:Soft iron Permanent magnet & (air gap) Ag Am Figure 1. Permanent magnet system. e
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