the periodic table information to write the conversion factor that belongs with the red arrow below. 6 PbO (s) + O2 (g) → 2 Pb;O4 (s) 8 Grams Milliliters Grams of PbO of O2 of Pb;O4 Охудen 15.999 82 Pb Moles of Moles of Moles of Lead 207.2 PbO (s) O2 (g) Pb;O4 (s)

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### Chemistry Conversion Factors Using the Balanced Chemical Equation

**Objective:**
Use the balanced equation and/or the periodic table information to write the conversion factor that belongs with the red arrow below.

**Equation:**
\[ 6 \text{ PbO (s)} + \text{ O}_2 \text{(g)} \rightarrow 2 \text{ Pb}_3\text{O}_4 \text{(s)} \]

**Periodic Table Information:**
- **Oxygen (O)**
  - Atomic number: 8
  - Atomic mass: 15.999

- **Lead (Pb)**
  - Atomic number: 82
  - Atomic mass: 207.2

**Diagram Explanation:**
The diagram illustrates the different steps involved in converting between grams and moles for the substances in the balanced chemical equation. There is a specific focus on converting between grams of PbO and moles of PbO, and identifying the appropriate conversion factor.

1. **Grams of PbO \( \rightarrow \) Moles of PbO (s)**:
   - This conversion factor is identified by the red arrow in the diagram. To convert grams of PbO to moles of PbO, you use the molar mass of PbO. PbO has a molar mass of 223.199 g/mol (Pb: 207.2 + O: 15.999).

2. **Milliliters of O2 \( \rightarrow \) Moles of O2 (g)**:
   - This involves using the molar volume of gases at standard temperature and pressure (STP), which is 22.4 L/mol.

3. **Moles of O2 (g) \( \rightarrow \) Moles of PbO (s)**:
   - This conversion uses the stoichiometric coefficients from the balanced chemical equation.

4. **Moles of PbO (s) \( \rightarrow \) Moles of Pb3O4 (s)**:
   - This again uses the stoichiometric coefficients from the balanced chemical equation.

5. **Moles of Pb3O4 (s) \( \rightarrow \) Grams of Pb3O4 (s)**:
   - This involves using the molar mass of Pb3O4.

**Key Conversion Factors:**
- 1 mole of PbO = 223.199 grams of PbO
- From the balanced equation, 6
Transcribed Image Text:### Chemistry Conversion Factors Using the Balanced Chemical Equation **Objective:** Use the balanced equation and/or the periodic table information to write the conversion factor that belongs with the red arrow below. **Equation:** \[ 6 \text{ PbO (s)} + \text{ O}_2 \text{(g)} \rightarrow 2 \text{ Pb}_3\text{O}_4 \text{(s)} \] **Periodic Table Information:** - **Oxygen (O)** - Atomic number: 8 - Atomic mass: 15.999 - **Lead (Pb)** - Atomic number: 82 - Atomic mass: 207.2 **Diagram Explanation:** The diagram illustrates the different steps involved in converting between grams and moles for the substances in the balanced chemical equation. There is a specific focus on converting between grams of PbO and moles of PbO, and identifying the appropriate conversion factor. 1. **Grams of PbO \( \rightarrow \) Moles of PbO (s)**: - This conversion factor is identified by the red arrow in the diagram. To convert grams of PbO to moles of PbO, you use the molar mass of PbO. PbO has a molar mass of 223.199 g/mol (Pb: 207.2 + O: 15.999). 2. **Milliliters of O2 \( \rightarrow \) Moles of O2 (g)**: - This involves using the molar volume of gases at standard temperature and pressure (STP), which is 22.4 L/mol. 3. **Moles of O2 (g) \( \rightarrow \) Moles of PbO (s)**: - This conversion uses the stoichiometric coefficients from the balanced chemical equation. 4. **Moles of PbO (s) \( \rightarrow \) Moles of Pb3O4 (s)**: - This again uses the stoichiometric coefficients from the balanced chemical equation. 5. **Moles of Pb3O4 (s) \( \rightarrow \) Grams of Pb3O4 (s)**: - This involves using the molar mass of Pb3O4. **Key Conversion Factors:** - 1 mole of PbO = 223.199 grams of PbO - From the balanced equation, 6
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