### Chemistry Conversion Factors Using the Balanced Chemical Equation**Objective:**Use the balanced equation and/or the periodic table information to write the conversion factor that belongs with the red arrow below.**Equation:**\[ 6 \text{ PbO (s)} + \text{ O}_2 \text{(g)} \rightarrow 2 \text{ Pb}_3\text{O}_4 \text{(s)} \]**Periodic Table Information:**- **Oxygen (O)** - Atomic number: 8 - Atomic mass: 15.999- **Lead (Pb)** - Atomic number: 82 - Atomic mass: 207.2**Diagram Explanation:**The diagram illustrates the different steps involved in converting between grams and moles for the substances in the balanced chemical equation. There is a specific focus on converting between grams of PbO and moles of PbO, and identifying the appropriate conversion factor.1. **Grams of PbO $ \rightarrow $ Moles of PbO (s)**: - This conversion factor is identified by the red arrow in the diagram. To convert grams of PbO to moles of PbO, you use the molar mass of PbO. PbO has a molar mass of 223.199 g/mol (Pb: 207.2 + O: 15.999).2. **Milliliters of O2 $ \rightarrow $ Moles of O2 (g)**: - This involves using the molar volume of gases at standard temperature and pressure (STP), which is 22.4 L/mol.3. **Moles of O2 (g) $ \rightarrow $ Moles of PbO (s)**: - This conversion uses the stoichiometric coefficients from the balanced chemical equation.4. **Moles of PbO (s) $ \rightarrow $ Moles of Pb3O4 (s)**: - This again uses the stoichiometric coefficients from the balanced chemical equation.5. **Moles of Pb3O4 (s) $ \rightarrow $ Grams of Pb3O4 (s)**: - This involves using the molar mass of Pb3O4.**Key Conversion Factors:**- 1 mole of PbO = 223.199 grams of PbO- From the balanced equation, 6

Given Reaction 6PbO(s) + O2(g) -------> 2 Pb3O4(s) Conversion factor from Grams of PbO…

the periodic table information to write the conversion factor that belongs with the red arrow below. 6 PbO (s) + O2 (g) → 2 Pb;O4 (s) 8 Grams Milliliters Grams of PbO of O2 of Pb;O4 Охудen 15.999 82 Pb Moles of Moles of Moles of Lead 207.2 PbO (s) O2 (g) Pb;O4 (s)

the periodic table information to write the conversion factor that belongs with the red arrow below. 6 PbO (s) + O2 (g) → 2 Pb;O4 (s) 8 Grams Milliliters Grams of PbO of O2 of Pb;O4 Охудen 15.999 82 Pb Moles of Moles of Moles of Lead 207.2 PbO (s) O2 (g) Pb;O4 (s)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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