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The period of oscillation for a pendulum on Earth is 9 seconds. If the given pendulum oscillates with a period of 22.1 seconds on the surface of the Moon, what is the acceleration due to gravity on the Moon's surface? Express your answer in both SI units (in m/s2) and U.s. Customary units (in ft/s2).

The period of oscillation for a pendulum on Earth is 9 seconds. If the given pendulum oscillates with a period of 22.1 seconds on the surface of the Moon, what is the acceleration due to gravity on the Moon's surface? Express your answer in both SI units (in m/s2) and U.s. Customary units (in ft/s2).

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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The period of oscillation for a pendulum on Earth is 9 seconds. If the given pendulum oscillates with a period of 22.1 seconds on the surface of the Moon, what is the acceleration due to gravity on the Moon's surface? Express your answer in both SI units (in m/s2) and U.S. Customary units (in ft/s2). acceleration in m/s? m/s² acceleration in ft/s2 ft/s2
Transcribed Image Text:The period of oscillation for a pendulum on Earth is 9 seconds. If the given pendulum oscillates with a period of 22.1 seconds on the surface of the Moon, what is the acceleration due to gravity on the Moon's surface? Express your answer in both SI units (in m/s2) and U.S. Customary units (in ft/s2). acceleration in m/s? m/s² acceleration in ft/s2 ft/s2
Expert Solution
Given Data

The period of oscillation for a pendulum on the Earth is TE=9 s.

The period of oscillation for a pendulum on the Moon is TM=22.1 s.

 

Standard Unit-

The acceleration due to gravity is gE=9.81 m/s2.

Step 1

The expression for the time of oscillation on Earth can be given as,

TE=2π×LgE

Here, L is the length of the pendulum and gE is the acceleration due to gravity on Earth.

Substitute the values in the above expression,

9 s=2π×L9.81 m/s2L=20.14 m

 

Similarly, the expression for the time of oscillation on Moon can be given as,

TM=2π×LgM

Here, gM is the acceleration due to gravity on Moon.

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