The perimeter of a rectangular garden is 48 feet. The length of the garden is 2 feet more than the width. Determine the dimensions of the garden by solving the following system of equations, where L and W represent the length and width of the garden. 2L+2W L = 48 = W+2 *** The width of the garden is feet. (Type an integer or a decimal.)
The perimeter of a rectangular garden is 48 feet. The length of the garden is 2 feet more than the width. Determine the dimensions of the garden by solving the following system of equations, where L and W represent the length and width of the garden. 2L+2W L = 48 = W+2 *** The width of the garden is feet. (Type an integer or a decimal.)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Transcribed Image Text:The perimeter of a rectangular garden is 48 feet. The length of the garden is 2 feet more than the width. Determine the
dimensions of the garden by solving the following system of equations, where L and W represent the length and width
of the garden.
2L+2W = 48
L
= W + 2
LUT
The width of the garden is feet. (Type an integer or a decimal.)
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