The perimeter of a rectangle is 60 yards. What are the dimensions of the rectangle with maximum area? Answer How to enter your answer Length: yards Width: yards

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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The perimeter of a rectangle is 60 yards. What are the dimensions of the rectangle with maximum area?
**Problem Statement:**

The perimeter of a rectangle is 60 yards. What are the dimensions of the rectangle with maximum area?

**Answer Section:**

- **Length:** [_____] yards
- **Width:** [_____] yards

**Instructions:**

To enter your answer, fill in the length and width in the provided spaces. The rectangle must have a perimeter of 60 yards, and you should determine the dimensions that provide the maximum area. 

**Explanation:**

For a rectangle with a given perimeter, the rectangle with the maximum area is a square. Use the perimeter formula \( P = 2 \times (\text{Length} + \text{Width}) \) to solve for the dimensions when the area is at its maximum.
Transcribed Image Text:**Problem Statement:** The perimeter of a rectangle is 60 yards. What are the dimensions of the rectangle with maximum area? **Answer Section:** - **Length:** [_____] yards - **Width:** [_____] yards **Instructions:** To enter your answer, fill in the length and width in the provided spaces. The rectangle must have a perimeter of 60 yards, and you should determine the dimensions that provide the maximum area. **Explanation:** For a rectangle with a given perimeter, the rectangle with the maximum area is a square. Use the perimeter formula \( P = 2 \times (\text{Length} + \text{Width}) \) to solve for the dimensions when the area is at its maximum.
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