The performance of students at a local community was recorded and categorized based on student's faculty. The gathered data was then analyzed by a statistician and the results obtained using MINITAB are shown below: Expected counts are printed below observed counts High Low Average Total Science 12 30 52 94 (15.67) (29.24) (49.09) Humanities 14 (10.67) 30 (33.42) 20 ** (19.91) Law 6 12 22 (*) (6.84) (11.49) Total 30 56 94 180 Chi-sq = 0.858 + 0.020 + *** + 1.042 0.000 + 0.350 + 0.030 + 0.104 + 0.023 =2.600 i. Define the null and alternative hypotheses of the x test for the above output. ii. Find the missing values **, ***, *****, Showing necessary working What is the degree of freedom for this test? iv. Estimate the p-value for this test. State the conclusion for the test. Give reason for your answer.

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please answer question 4 and 5

The performance of students at a local community was recorded and categorized based on student's
faculty. The gathered data was then analyzed by a statistician and the results obtained using
MINITAB are shown below:
Expected counts are printed below observed counts
Low
Average
High
Total
Science
12
30
52
94
(15.67)
(29.24)
(49.09)
Humanities
20
30
14
**
(10.67)
(19.91)
(33.42)
Law
4
6
12
22
(*)
(6.84)
(11.49)
Total
30
56
94
180
Chi-sq
0.858 +
0.020 +
*** +
1.042
0.000 +
0.350 +
0.030 + 0.104 + 0.023
=2.600
Define the null and alternative hypotheses of the x test for the above output.
ii. Find the missing values **, ***, ****, Showing necessary working
iii. What is the degree of freedom for this test?
Estimate the p-value for this test.
State the conclusion for the test. Give reason for your answer.
i.
iv.
V.
Transcribed Image Text:The performance of students at a local community was recorded and categorized based on student's faculty. The gathered data was then analyzed by a statistician and the results obtained using MINITAB are shown below: Expected counts are printed below observed counts Low Average High Total Science 12 30 52 94 (15.67) (29.24) (49.09) Humanities 20 30 14 ** (10.67) (19.91) (33.42) Law 4 6 12 22 (*) (6.84) (11.49) Total 30 56 94 180 Chi-sq 0.858 + 0.020 + *** + 1.042 0.000 + 0.350 + 0.030 + 0.104 + 0.023 =2.600 Define the null and alternative hypotheses of the x test for the above output. ii. Find the missing values **, ***, ****, Showing necessary working iii. What is the degree of freedom for this test? Estimate the p-value for this test. State the conclusion for the test. Give reason for your answer. i. iv. V.
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