The percentage of people given an antirheumatoid who suffer severe, moderate, or minor side effects are 14, 20 and 66%,respectively. Assume that people react independently and that 20 people are given the medicine. Determine the following.Round your answers to four decimal places (e.g. 98.7654).(a) The probability 2, 4, and 14 people will suffer severe, moderate, or minor side effects, respectively.Probability i(b) The probability that no one will suffer severe side effects.Probability = i(c) The mean and variance of the number of people who will suffer severe side effects.Mean = iVariance =

From the given information ,Let X be the number of people who suffer severe side effects.Y be the…

Answered: The percentage of people given an…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Find the probability of the indicated event if P(E)= 0.40 and P(F)=0.50. Find P(E or F) if P(E and F) = 0.05. P(E or F) = (Simplify your answer.)
Answer part a and b
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Find the probability P(not E) if P(E)= 0.18. The probability P(not E) is (Simplify your answer.)
Find the probability of the indicated event if P(E) = 0.20 and P(F) = 0.40. Find P(E or F) if P(E and F) = 0.20. P(E or F) = (Simplify your answer.)
At a certain University, the chance of a student receiving financial aid is 87%. 15 students are randomly and independently chosen. Use R/Rcmdr to find the probability that at most 12 of them are receiving financial aid. ROUND YOUR FINAL ANSWER TO 3 DECIMALS. Choose the most correct (closest) answer below? a.0.6916319 b.0.1204051 c.0.1879631 d.0.3083681
Find the indicated probability and interpret the result. From 1975 through 2020, the mean annual gain of the Dow Jones Industrial Average was 653. A random sample of 34 years is selected from this population. What is the probability that the mean gain for the sample was between 400 and 800? Assume o = 1540. The probability is (Round to four decimal places as needed.) Interpret the result. Select the correct choice and fill in the answer box to complete your choice. (Round to two decimal places as needed.) O A. About OB. About OC. About OD. About % of samples of 46 years will have an annual mean gain between 400 and 800. % of samples of 34 years will have an annual mean gain between 653 and 800. % of samples of 34 years will have an annual mean gain between 400 and 800. % of sampl of 34 years will have an annual mean gain between 400 and 653.
Find the indicated probability. If P(A or B) = 0.8, P(A) = 0.3, and P(A and B) = 0.15, find P(B). P(B) =| (Simplify your answer. Type an integer or a decimal.)
8
The mean percent of childhood asthma prevalence in 43 cities is 2.38%. A random sample of 30 of these cities is selected. What is the probability that the mean childhood asthma prevalence for the sample is greater than 2.8%? Interpret this probability. Assume that o = 1.25%. The probability is (Round to four decimal places as needed.) Interpret this probability. Select the correct choice below and fill in the answer box to complete your choice. (Round to two decimal places as needed.) O A. About % of samples of 43 cities will have a mean childhood asthma prevalence greater than 2.8%. O B. About % of samples of 30 cities will have a mean childhood asthma prevalence greater than 2.38%. O C. About % of samples of 30 cities will have a mean childhood asthma prevalence greater than 2.8%. Click to select your answer(s). P Type here to search 99+ a (? 1:42 PM 4/11/2021 ho insen 144 ese & t backspace %23 3. %24 4 6. 8 2. Y W tab H. J. K pase 5 R
i need the answer quickly
A marketing company has randomly surveyed 210 men who watch professional sports. The men were separated according to their educational level (college degree or not) and whether they preferred the NBA or the National Football League (NFL). The results of the survey are shown to the right. Complete parts a through d. a. What is the probability that a randomly selected survey participant prefers the NFL? 0.5286 (Round to four decimal places as needed.) b. What is the probability that randomly selected survey participant has a college degree and prefers the NBA? 0.1857 (Round to four decimal places as needed.) c. Suppose a survey participant is randomly selected and you are told that he has a college degree. What is the probability that this man prefers the NFL? (Round to four decimal places as needed.) C Sports Preference NBA NFL College No College Degree 39 13 Degree 60 98

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