### Chemical Composition CalculationThe percent by mass of **iron (III)** in **Fe₂S₃** is: `[Enter your answer here] %`---\[ Submit Answer \]### Explanation:To calculate the percentage by mass of iron (III) in iron(III) sulfide (Fe₂S₃), follow these steps:1. **Determine the molar mass of Fe₂S₃:** - Iron (Fe): Atomic mass = 55.85 u (approx) - Sulfur (S): Atomic mass = 32.07 u (approx) Formula: (2 * 55.85) + (3 * 32.07) Calculation: 111.70 + 96.21 = 207.91 u2. **Calculate the mass percentage of iron:** - Mass of iron in Fe₂S₃ = 2 * 55.85 = 111.70 u - Total molar mass of Fe₂S₃ = 207.91 u Percentage by mass = (Mass of iron / Total molar mass) * 100 - Percentage by mass = (111.70 / 207.91) * 100 ≈ 53.73 %Fill the answer and submit it in the provided system.Note: Make sure to double-check your atomic masses with the periodic table as values being used in standard calculations might slightly differ based on precision.

we have to calculate the mass percentage of Fe(III)

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The percent by mass of iron (III) in Fe₂S3 is %.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

### Chemical Composition Calculation

The percent by mass of **iron (III)** in **Fe₂S₃** is:

`[Enter your answer here] %`

---

\[ Submit Answer \]

### Explanation:
To calculate the percentage by mass of iron (III) in iron(III) sulfide (Fe₂S₃), follow these steps:

1. **Determine the molar mass of Fe₂S₃:**
- Iron (Fe): Atomic mass = 55.85 u (approx)
- Sulfur (S): Atomic mass = 32.07 u (approx)

Formula: (2 * 55.85) + (3 * 32.07)
Calculation: 111.70 + 96.21 = 207.91 u

2. **Calculate the mass percentage of iron:**
- Mass of iron in Fe₂S₃ = 2 * 55.85 = 111.70 u
- Total molar mass of Fe₂S₃ = 207.91 u

Percentage by mass = (Mass of iron / Total molar mass) * 100
- Percentage by mass = (111.70 / 207.91) * 100 ≈ 53.73 %

Fill the answer and submit it in the provided system.

Note: Make sure to double-check your atomic masses with the periodic table as values being used in standard calculations might slightly differ based on precision.

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