The Pear company sells pPhones. The cost to manufacture #pPhones is C(x) = -24x² +62000 + 20017 dollars (this includes overhead costs and production costs for pPhone). If the company sells a pPhones for the maximum price they can fetch, the revenue function be R(x) = -28x² + 182000 dollars. How many pPhones should the Pear company produce and sell to maximimze profit? (Remember that profit=revenue-cost.)

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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The Pear company sells pPhones. The cost to manufacture z pPhones is
C(x) = -24x² +62000x + 20017 dollars (this includes overhead costs and production costs for each
pPhone). If the company sells z pPhones for the maximum price they can fetch, the revenue function will
be R(x) = -28x² + 182000 dollars.
How many pPhones should the Pear company produce and sell to maximimze profit? (Remember that
profit=revenue-cost.)
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Transcribed Image Text:The Pear company sells pPhones. The cost to manufacture z pPhones is C(x) = -24x² +62000x + 20017 dollars (this includes overhead costs and production costs for each pPhone). If the company sells z pPhones for the maximum price they can fetch, the revenue function will be R(x) = -28x² + 182000 dollars. How many pPhones should the Pear company produce and sell to maximimze profit? (Remember that profit=revenue-cost.) Question Help: Video Submit Question
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