The path r(t) = (t- sin t) i+ (1- cos t) j describes motion on the cycloid x=t- sin t, y=1- cos t. Find the particle's velocity and acceleration vectors at t=- and sketch them as vectors on the curve. .....

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**Cycloid Motion and Vector Analysis**

The path \( \mathbf{r}(t) = (t - \sin t) \, \mathbf{i} + (1 - \cos t) \, \mathbf{j} \) describes motion on the cycloid \( x = t - \sin t, \, y = 1 - \cos t \). Find the particle's velocity and acceleration vectors at \( t = \frac{\pi}{2} \), and sketch them as vectors on the curve.

**Solution Approach:**

1. **Position Function**: The particle’s position at time \( t \) is given by:
   \[
   \mathbf{r}(t) = (t - \sin t) \, \mathbf{i} + (1 - \cos t) \, \mathbf{j}
   \]

2. **Velocity Vector**: Derive the velocity \( \mathbf{v}(t) \) by differentiating the position function \( \mathbf{r}(t) \) with respect to time \( t \):
   \[
   \mathbf{v}(t) = \frac{d}{dt}[(t - \sin t) \, \mathbf{i} + (1 - \cos t) \, \mathbf{j}]
   \]

3. **Acceleration Vector**: Derive the acceleration \( \mathbf{a}(t) \) by differentiating the velocity function \( \mathbf{v}(t) \) with respect to time \( t \):
   \[
   \mathbf{a}(t) = \frac{d}{dt}[\mathbf{v}(t)]
   \]

4. **Evaluate at \( t = \frac{\pi}{2} \)**: Substitute \( t = \frac{\pi}{2} \) into \(\mathbf{v}(t)\) and \(\mathbf{a}(t)\) to find the specific vectors at this point.

5. **Sketch the Vectors**: Illustrate both the velocity and acceleration vectors on the curve at \( t = \frac{\pi}{2} \).

This analysis helps in understanding the dynamics of motion along a cycloidal path commonly encountered in physics and engineering applications.
Transcribed Image Text:**Cycloid Motion and Vector Analysis** The path \( \mathbf{r}(t) = (t - \sin t) \, \mathbf{i} + (1 - \cos t) \, \mathbf{j} \) describes motion on the cycloid \( x = t - \sin t, \, y = 1 - \cos t \). Find the particle's velocity and acceleration vectors at \( t = \frac{\pi}{2} \), and sketch them as vectors on the curve. **Solution Approach:** 1. **Position Function**: The particle’s position at time \( t \) is given by: \[ \mathbf{r}(t) = (t - \sin t) \, \mathbf{i} + (1 - \cos t) \, \mathbf{j} \] 2. **Velocity Vector**: Derive the velocity \( \mathbf{v}(t) \) by differentiating the position function \( \mathbf{r}(t) \) with respect to time \( t \): \[ \mathbf{v}(t) = \frac{d}{dt}[(t - \sin t) \, \mathbf{i} + (1 - \cos t) \, \mathbf{j}] \] 3. **Acceleration Vector**: Derive the acceleration \( \mathbf{a}(t) \) by differentiating the velocity function \( \mathbf{v}(t) \) with respect to time \( t \): \[ \mathbf{a}(t) = \frac{d}{dt}[\mathbf{v}(t)] \] 4. **Evaluate at \( t = \frac{\pi}{2} \)**: Substitute \( t = \frac{\pi}{2} \) into \(\mathbf{v}(t)\) and \(\mathbf{a}(t)\) to find the specific vectors at this point. 5. **Sketch the Vectors**: Illustrate both the velocity and acceleration vectors on the curve at \( t = \frac{\pi}{2} \). This analysis helps in understanding the dynamics of motion along a cycloidal path commonly encountered in physics and engineering applications.
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