The particle P starts from rest at point A at time t = 0 and changes its speed thereafter at a constant rate of 2.1g as it follows the horizontal path shown. Determine the magnitude and direction of its total acceleration at times t = 0.82 s and t = 1.26 s. State your directions relative to the x-axis shown (CCW positive) and choose the angle with the smallest magnitude. Note: 12.55769377 and 0.7321 have been attempted and they were both incorrect. Thank you and have a nice day ahead.

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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The particle P starts from rest at point A at time t = 0 and changes its speed thereafter at a constant rate of 2.1g as it follows the horizontal path shown. Determine the magnitude and direction of its total acceleration at times t = 0.82 s and t = 1.26 s. State your directions relative to the x-axis shown (CCW positive) and choose the angle with the smallest magnitude.

Note: 12.55769377 and 0.7321 have been attempted and they were both incorrect. Thank you and have a nice day ahead.

The particle P starts from rest at point A at time t = 0 and changes its speed thereafter at a constant rate of 2.1g as it follows the
horizontal path shown. Determine the magnitude and direction of its total acceleration at times t = 0.82 s andt = 1.26 s. State your
directions relative to the x-axis shown (CCW positive) and choose the angle with the smallest magnitude.
-2.95 m-
3.63 m
Answers:
Att = 0.82 s, a =
81.269
m/s?, e =
i
!
Att = 1.26 s, a =
20.601
m/s?, e =
180
Transcribed Image Text:The particle P starts from rest at point A at time t = 0 and changes its speed thereafter at a constant rate of 2.1g as it follows the horizontal path shown. Determine the magnitude and direction of its total acceleration at times t = 0.82 s andt = 1.26 s. State your directions relative to the x-axis shown (CCW positive) and choose the angle with the smallest magnitude. -2.95 m- 3.63 m Answers: Att = 0.82 s, a = 81.269 m/s?, e = i ! Att = 1.26 s, a = 20.601 m/s?, e = 180
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