---### Physics Problem: Speed of a Particle on a Circular Path#### Problem Statement:A particle is moving on a circular path with a radius of 2.5 m. At point \( A \), the particle's speed is \( v_A = 5 \, \text{m/s} \), and this speed is increasing at a constant rate of \( 1.5 \, \text{m/s}^2 \). Determine its speed at point \( B \).#### Diagram Explanation:- The provided diagram shows a circular path (red circle) with a radius of 2.5 m.- The circle is centered on the origin of a coordinate system.- Point \( A \) is at the rightmost point of the circle on the horizontal axis.- Point \( B \) is at the topmost point of the circle on the vertical axis.- The speed \( v_A \) of the particle at point \( A \) is 5 m/s, moving vertically upward.- The diagram includes the notation \( v_A = 5 \, \text{m/s} \).#### Possible Answers:- \( v_B = 3.64 \, \text{m/s} \)- \( v_B = 6.06 \, \text{m/s} \)- \( v_B = 6.97 \, \text{m/s} \)- \( v_B = 8.49 \, \text{m/s} \)---This setup helps students understand the given scenario, visualize the circular motion, and apply the principles of circular dynamics to solve for the speed at a different point on the path.

Given , Speed is increasing at a constant rate of 1.5 m/s2.

The particle on the circular path has a speed v A = 5 m/s at point A, which is increasing at a constant rate of 1.5m/s2. What is its speed at point B? B \AVA = 5 m/s छ A 2.5 Im O UB = 3.64m/s UB = 6.06m/s UB = 6.97m/s O "B = 8.49m/s

The particle on the circular path has a speed v A = 5 m/s at point A, which is increasing at a constant rate of 1.5m/s2. What is its speed at point B? B \AVA = 5 m/s छ A 2.5 Im O UB = 3.64m/s UB = 6.06m/s UB = 6.97m/s O "B = 8.49m/s

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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