The particle of mass m- 2.3 kg is attached to the end of the light rigid bar of length L - 0.83 m. The system is released from rest while in the horizontal position shown, at which the torsional spring is undeflected. The bar is then observed to rotate 45° before stopping momentarily, (a) Determine the value of the torsional spring constant k;. (b) For this value of kr, determine the speed v of the particle when e - 25°. L Part 1 Position 1 is the horizontal orientation shown in the figure. Position 2 is the orientation when e- 45 Find the kinetic energy in positions 1 and 2. Answers: Answers: (a) ky= Nem/rad (b) v m/s

Structural Analysis
6th Edition
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Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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The particle of mass m = 2.3 kg is attached to the end of the light rigid bar of length L = 0.83 m. The system is released from rest while
in the horizontal position shown, at which the torsional spring is undeflected. The bar is then observed to rotate 45° before stopping
momentarily, (a) Determine the value of the torsional spring constant kr. (b) For this value of kr, determine the speed vof the particle
when e = 25°.
kT
Part 1
Position 1 is the horizontal orientation shown in the figure. Position 2 is the orientation when e- 45. Find the kinetic energy in
positions 1 and 2.
Answers:
T1-
kg m²/s2
T2-
kg m²/s?
Answers:
(a) ky =
i
Nem/rad
(b)
m/s
Transcribed Image Text:The particle of mass m = 2.3 kg is attached to the end of the light rigid bar of length L = 0.83 m. The system is released from rest while in the horizontal position shown, at which the torsional spring is undeflected. The bar is then observed to rotate 45° before stopping momentarily, (a) Determine the value of the torsional spring constant kr. (b) For this value of kr, determine the speed vof the particle when e = 25°. kT Part 1 Position 1 is the horizontal orientation shown in the figure. Position 2 is the orientation when e- 45. Find the kinetic energy in positions 1 and 2. Answers: T1- kg m²/s2 T2- kg m²/s? Answers: (a) ky = i Nem/rad (b) m/s
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