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The partial fraction decomposition of 6x2 22x+32 x(x-2)² can be written in the form of f(x) g(x) + + I 2 h(x) (x-2)² where I f(x) = g(x) = h(x) = Question Help: Message instructor (7x3+8x2+8x+24 Consider the indefinite integral dx. x4 + 4x² The integrand has partial fractions decomposition a b + where a = b = = c = d + I cx+d Integrating term by term, we obtain that 7x3+8x²+8x + 24 dx = x4 + 4x² +C

The partial fraction decomposition of 6x2 22x+32 x(x-2)² can be written in the form of f(x) g(x) + + I 2 h(x) (x-2)² where I f(x) = g(x) = h(x) = Question Help: Message instructor (7x3+8x2+8x+24 Consider the indefinite integral dx. x4 + 4x² The integrand has partial fractions decomposition a b + where a = b = = c = d + I cx+d Integrating term by term, we obtain that 7x3+8x²+8x + 24 dx = x4 + 4x² +C

College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter6: Linear Systems
Section6.6: Partial Fractions
Problem 52E
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The partial fraction decomposition of 6x2 22x+32 x(x-2)² can be written in the form of f(x) g(x) + + I 2 h(x) (x-2)² where I f(x) = g(x) = h(x) = Question Help: Message instructor
Transcribed Image Text:The partial fraction decomposition of 6x2 22x+32 x(x-2)² can be written in the form of f(x) g(x) + + I 2 h(x) (x-2)² where I f(x) = g(x) = h(x) = Question Help: Message instructor
(7x3+8x2+8x+24 Consider the indefinite integral dx. x4 + 4x² The integrand has partial fractions decomposition a b + where a = b = = c = d + I cx+d Integrating term by term, we obtain that 7x3+8x²+8x + 24 dx = x4 + 4x² +C
Transcribed Image Text:(7x3+8x2+8x+24 Consider the indefinite integral dx. x4 + 4x² The integrand has partial fractions decomposition a b + where a = b = = c = d + I cx+d Integrating term by term, we obtain that 7x3+8x²+8x + 24 dx = x4 + 4x² +C
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