The oxidation of NH4+ to NO3- in acid solution (pH = 5.600) is described by the following equation: $$ The overall reaction for the oxidation has an E\deg cell = -0.2710 V. E\deg = 1.50 V for the half-reaction $$ 2nd attempt See Hint Be sure to solve the equation using a base-10 logarithm (log) rather than the natural logarithm (In ). What is the ratio of [NO3-] to [NH4+] at 298 K if PO2 = 0.180 atm? Assume that the reaction is at equilibrium.
The oxidation of NH4+ to NO3- in acid solution (pH = 5.600) is described by the following equation: $$ The overall reaction for the oxidation has an E\deg cell = -0.2710 V. E\deg = 1.50 V for the half-reaction $$ 2nd attempt See Hint Be sure to solve the equation using a base-10 logarithm (log) rather than the natural logarithm (In ). What is the ratio of [NO3-] to [NH4+] at 298 K if PO2 = 0.180 atm? Assume that the reaction is at equilibrium.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![The oxidation of NH4+ to NO3- in acid solution (pH
=
5.600) is described by the following equation:
$$
The overall reaction for the oxidation has an E\deg
cell = -0.2710 V.
E\deg = 1.50 V for the half-reaction
$$
2nd attempt
See Hint
Be sure to solve the equation using a base-10
logarithm (log) rather than the natural logarithm (In
).
What is the ratio of [NO3-] to [NH4+] at 298 K if
PO2 = 0.180 atm? Assume that the reaction is at
equilibrium.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5fc7f244-af13-4d97-93de-4463ab5b1cc6%2F3ddf2e85-215e-44ce-85c9-c380a752ff46%2Flwrvw8h_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The oxidation of NH4+ to NO3- in acid solution (pH
=
5.600) is described by the following equation:
$$
The overall reaction for the oxidation has an E\deg
cell = -0.2710 V.
E\deg = 1.50 V for the half-reaction
$$
2nd attempt
See Hint
Be sure to solve the equation using a base-10
logarithm (log) rather than the natural logarithm (In
).
What is the ratio of [NO3-] to [NH4+] at 298 K if
PO2 = 0.180 atm? Assume that the reaction is at
equilibrium.
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