The oxidation of NH4+ to NO3- in acid solution (pH = 5.600) is described by the following equation: $$ The overall reaction for the oxidation has an E\deg cell = -0.2710 V. E\deg = 1.50 V for the half-reaction $$ 2nd attempt See Hint Be sure to solve the equation using a base-10 logarithm (log) rather than the natural logarithm (In ). What is the ratio of [NO3-] to [NH4+] at 298 K if PO2 = 0.180 atm? Assume that the reaction is at equilibrium.

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Chapter1: Chemical Foundations
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The oxidation of NH4+ to NO3- in acid solution (pH
=
5.600) is described by the following equation:
$$
The overall reaction for the oxidation has an E\deg
cell = -0.2710 V.
E\deg = 1.50 V for the half-reaction
$$
2nd attempt
See Hint
Be sure to solve the equation using a base-10
logarithm (log) rather than the natural logarithm (In
).
What is the ratio of [NO3-] to [NH4+] at 298 K if
PO2 = 0.180 atm? Assume that the reaction is at
equilibrium.
Transcribed Image Text:The oxidation of NH4+ to NO3- in acid solution (pH = 5.600) is described by the following equation: $$ The overall reaction for the oxidation has an E\deg cell = -0.2710 V. E\deg = 1.50 V for the half-reaction $$ 2nd attempt See Hint Be sure to solve the equation using a base-10 logarithm (log) rather than the natural logarithm (In ). What is the ratio of [NO3-] to [NH4+] at 298 K if PO2 = 0.180 atm? Assume that the reaction is at equilibrium.
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