The oxidation of HNO₂ to NO3 in acid solution is a 4-electron transfer reaction described by the following equation: 2HNO₂ (aq) + 0₂ (8) 2NO3 (aq) + 2H+ (aq) E° cell 0.289 V If the reaction at 298 K is in equilibrium with air (Po2 = 0.150 atm) at pH 5.60, what is the ratio of [NO3] to [HNO₂]?

The oxidation of HNO₂ to NO3 in acid solution is a 4-electron transfer reaction described by the following equation: 2HNO₂ (aq) + 0₂ (8) 2NO3 (aq) + 2H+ (aq) E° cell 0.289 V If the reaction at 298 K is in equilibrium with air (Po2 = 0.150 atm) at pH 5.60, what is the ratio of [NO3] to [HNO₂]?

Chemistry

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ISBN:9781305957404

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Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

The oxidation of HNO2 to NO3 in acid solution is a 4-electron transfer reaction described by the following equation:
2HNO₂ (aq) + O₂(g)
If the reaction at 298 K is in equilibrium with air (Po2 = 0.150 atm) at pH 5.60, what is the ratio of [NO3] to [HNO₂]?
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Write your answer in scientific notation containing three significant figures.
1.47
> 2NO3 (aq) + 2H+ (aq) Ecell = 0.289 V
E°
x 10
12
See Periodic Table
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