The owner of Prices Limited claims that 75% of all items in the store are 1 point less than $5. Suppose you check a random sample of 146 items and find that 105 have prices less than $5.Test the claim at the .01 level of significance. 12. Based on your answers above, what is your conclusion? (a) Do not reject Ho (b) Reject He (c) Cannot determine O A O c O B
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- The median price of homes in in a certain city was $228,830. A sample of 200 homes sold in a suburb of the city found 113 homes with sales prices over $228,830 and 87 homes with sales prices under $228,830. Can you conclude that the median price of homes in the suburb differs from the median price of homes in the entir city? Use a = 0.05. State the null and alternative hypotheses. O Ho: Median # 228,830 H₂: Median = 228,830 O Ho: Median 2 228,830 H₂: Median 228,830 O Ho: Median > 228,830 H₂: Median = 228,830 Find the value of the test statistic. (Round your answer to two decimal places.) z = Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. O Do not reject Ho. There is sufficient evidence to conclude that the median price of homes in the suburb differs significantly from $228,830. Do not reject Ho. There is not sufficient evidence to conclude that the median price of homes in the suburb differs significantly from $228,830. O Reject Ho.…Which of the following statements are true?a. Obtain the cdf of X. b. What is P(X ≤ .5)? c. Using the cdf from (a), what is P(.25 < X ≤ .5)? d. What is the 75th percentile of the distribution?
- Surprisingly, a study found that children under stress reported fewer symptoms of depression and anxiety but scored higher on a Lie Scale (a measure of tendency to give socially desirable responses). The population mean for the Lie Scale for nonstressed children is 3.8. The sample of 24 children's scores are listed below. Test the hypothesis that children under stress are more likely to give socially desirable answers. Write a complete conclusion in the context of the problem. 2.9 3.3 5.0 3.7 3.9 3.7 3.4 4.3 4.2 3.8 4.7 4.1 4.3. 3.6. 4.6. 2.9. 4.2. 4.0. 4.5. 4.4 4.0. 3.5 4.4. 4.7Q. 4 For a research project, suppose you want to compare the mean from a sample of 21 students against a known population mean of 100. You obtain a X = 105. Although you do not know o x you have calculated S x = 20. a. What are Ho and Ha ? b. What is your tobt? c. Comparing tobt to terit, What do you conclude? (CNNBC recently reported that the mean annual cost of auto insurance is 1035 dollars. Assume the standard deviation is 126 dollars. You will use a simple random sample of 142 auto insurance policies. Find the probability that a single randomly selected policy has a mean value between 1012.8 and 1049.8 dollars. P(1012.88) Each of 49 subjects tastes two unmarked cups of coffee and says which he or she prefers. One cup in each pair contains instant coffee, the other fresh-brewed coffee. 30 of the subjects prefer the fresh-brewed coffee. Take p to be the proportion of the population who would prefer fresh-brewed coffee in a blind tasting. Test the claim that a majority of people prefer the taste of fresh-brewed coffee.(a) H0: p = ? and Ha: p > ?(b) What is the test statistic? (Use 2 decimal places)(c) What is the p-value? (Use 4 decimal places)A. Fail to reject H, because the P-value, 0.0433, is greater than a = 0.05. B. Fail to reject H, because the P-value, 0.0433, is less than a = 0.05. C. Reject Ho because the P-value, 0.0433, is greater than a = 0.05, D. Reject Ho because the P-value, 0.0433, is less than a= 0.05. Do you reject or fail to reject H, at the 0.10 level of significance? A. Fail to reject Ho because the P-value, 0.0433, is less than a = 0.10.Need the claim, hypothesis, crit value(s), rejection regions, d, Sd, t test, reject or fail to, and conclusion.The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a = 0.01, (b) a=0.05, and (c) a=0.10. P= 0.0545 (a) Do you reject or fail to reject H, at the 0.01 level of significance? O A. Reject H, because the P-value, 0.0545, is less than a= 0.01. O B. Fail to reject H, because the P-value, 0.0545, is greater than a = 0.01. O C. Fail to reject H, because the P-value, 0.0545, is less than a = 0.01. O D. Reject Ho because the P-value, 0.0545, is greater than a = 0.01,need help with bA simple random sample of size n= 16 is drawn from a population that is normally distributed. The sample mean is found to be x= 21.2 and the sample standard deviation is found to be s= 6.5. Determine if the population mean is different from 26 at the a= 0.05 level of significance. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). Click here to view the table of criticaltevalmes (a) Determine the null and alternative hypotheses. Ho H,: (Type integers or decimals. Do not round.) (b) Identify the test statistic. (Round to two decimal places as needed.) Approximate the P-value. The P-value is in the range (c) State the conclusion for the test.SEE MORE QUESTIONS