The overhead reach distances of adult females are normally distributed with a mean of 202.5 cm and a standard deviation of 7.8 cm. a. Find the probability that an individual distance is greater than 212.50 cm. b. Find the probability that the mean for 20 randomly selected distances is greater than 201.00 cm. c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30? a. The probability is [ (Round to four decimal places as needed.) b. The probability is I (Round to four decimal places as needed.) c. Choose the correct answer below. O A. The normal distribution can be used because the original population has a normal distribution. B. The normal distribution can be used because the probability is less than 0.5 OC. The normal distribution can be used because the finite population correction factor is small. O D. The normal distribution can be used because the mean is large.

Q: メ+1

A:

Q: A = 6 -2 -2 10 -3 5 1 ---3-0 C=0-2 a = 1, b = [3 08]. -10 1 . B 5 2 11 9 4 4 7 0 0 11

A: We have to solve given Questions.

Q: 40 -50-

A:

Q: . 3류 - 2층 : 3% +4/3) 1

A:

Q: 10 8/10 + 9 7/12=

A:

Q: 2) 36³x=¹

A:

Q: 1+3+5+7...+1003

A: Sum of n odd numbers, where the last term of the series is (2n – 1), is, Sn = 1 + 3 + 5 + …. + (2n –…

Q: 33/29 b.

A:

Q: Poove BLO => YQ< B.

A:

Q: FIND S + 4 (s² – 8S + 6) -

A:

Q: expand (a-b)7

A: The solution is given in the next step.

Q: sing the geometry of the graph ,evalvate the definite integrals.

A: As this is a multiple subpart question according to the Bartleby Answering rule, only first three…

Q: 7 2 3k+1= [A] k = 2

A: Consider the equation ∑n=273k+1=A We have to find the value of A Expand the summation of left hand…

Q: 5. 110 (x + 12)°

A: given alternate exterior angles are equal.

Q: 6   9,171.6

A:

Q: 81 (1) 420

A:

Q: Evaluate (33)2

A: Given: 332Power rule amn=am×nSolution:332=33×2=36(33)2=729

Q: 4. Fill in the following contingency table with the number of observations that fall into each com-…

A: x1 = number of colored oranges from Skittles brand = 77 x2 = number of colored oranges from M &amp;…

Q: (n + 4)3 =

A: Given query is to expand (n+4)3

Q: 12 16

A: We know that If a perpendicular is drawn from the vertex of right angle triangle of a right triangle…

Q: 38 10

A:

Q: expansion of (1-2m)“

A:

Q: 10| 5 10 10 -5 -5

A:

Q: 18(9+7)+3

A: 18(9+7)+3

Q: 29 Using the combination formula expand (5+x)

A:

Q: 6. Using the data from the contingency table, obtain the value of the test statistic of our test. 7.…

A: Step 1: Given: x1 = number of colored oranges from Skittles brand = 77 x2 = number of colored…

Q: 11.6 - (-12.2) + (11.7)

A:

Q: 3(m – 5) + m

A: 3(m-5)+m=0 3m-15+m=0 add both side 15 we get 2m=15

Q: 5 -10-8 -6 14 -2 2 4 6 8 10 3 4 5 6 7 1

A: Step 1:To find  limx→−2−​f(x)The expression refers to the left-hand limit of f(x) at -2. Meaning we…

Q: 8(14-9)+5 32+6

A: The given expression is