The following question has multiple parts; please work them in the order shown.**Part A) What is the normal force on the box?**- Diagram: A block labeled "42 kg" is placed on an inclined plane with an angle of 25°.- Normal Force (Fₙ): [_____] [_____]- Units: [_____] [_____]- **Direction Options:** - Green arrow (perpendicular to the plane) - Purple arrow - Orange arrow - Red arrows (three options pointing at different angles parallel to the plane)---**Part B) If the coefficient of friction is μ = 0.17, what is the maximum force of friction?**- Maximum Force of Friction (F_f): [_____] [_____]- Units: [_____] [_____]---**Part C) What would the net force on the block be?**- Net Force (F_net): [_____] [_____]- Units: [_____] [_____]- **Direction Options:** - Green arrow (perpendicular to the plane) - Purple arrow - Orange arrow - Red arrows (three options pointing at different angles parallel to the plane)---**Part D) What then would be the acceleration of the object?**- Acceleration (a): [_____] [_____]- Units: [_____] [_____]- **Direction Options:** - Green arrow (perpendicular to the plane) - Purple arrow - Orange arrow - Red arrows (three options pointing at different angles parallel to the plane)---This exercise focuses on calculating various physical dynamics acting on a block situated on an inclined plane, including normal force, frictional force, net force, and acceleration, while identifying their respective directions.

Answered: Image /qna-images/answer/70e11416-2a41-4c5e-9051-355551783116.jpg

the order shown. Part A) What is the normal force on the box? 42kg 25 FN - | unit Pick a direction from the options below Part B) If the coefficient of friction is u = 0.17, what is the maximum force of friction? Ff = Junit Part C) What would the net force on the block be? Fnet ) unit[ Pick a direction from the options below Part D) What then would be the acceleration of the object? ]unit Pick a direction from the options below

the order shown. Part A) What is the normal force on the box? 42kg 25 FN - | unit Pick a direction from the options below Part B) If the coefficient of friction is u = 0.17, what is the maximum force of friction? Ff = Junit Part C) What would the net force on the block be? Fnet ) unit[ Pick a direction from the options below Part D) What then would be the acceleration of the object? ]unit Pick a direction from the options below

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Using the component method, determine the resultant force and the equilibrant force of each of the following sets of concurrent forces. 1. F₁ = 380 N @ 50⁰ N of E F2 = 650 N @ 22⁰ E of S F3 = 720 N West 3. FA = 20 lb S А FB = 24 lb NE Fc = 16 lb West FD = 25 lb @ 32º E of S A FOLLOW THE FORMAT BELOW Example 2: F₁ = 200 d West F₂ = 300 d @ 35⁰ W of N F3 = 250 d SE F₁ = 450 d @ 80⁰ S of W Σ Fx -200 (West) 300(sin 35⁰) =-172 (West) 250(cos 45°) = +177 (East) 450(cos 80°) = -78.1 (West) 2. F₁ = 332 d @ 35⁰ W of N F2 = 420 d @ 75⁰ E of N F3 = 108 d SW -273 (West) Fy 0 300(cos 35°) =+246 (North) 45⁰ = -177 (South) 450(sin 80°) =-443 (South) -374 (South) Sketch F₁ = 200 d F₂=300 d FAY! F3-250 d 45⁰ F t 80⁰ 35⁰1 F2y F3v F4=150 d ANSWER NO. 2 ONLY
Please draw the free diagram clear and also indicate if we need to add force
Using the component method, determine the resultant force and the equilibrant force of each of the following sets of concurrent forces. 1. F₁ = 380 N @ 50⁰ N of E F2 = 650 N @ 22⁰ E of S F3 = 720 N West 3. FA = 20 lb S А FB = 24 lb NE Fc = 16 lb West FD = 25 lb @ 32º E of S A FOLLOW THE FORMAT BELOW Example 2: F₁ = 200 d West F₂ = 300 d @ 35⁰ W of N F3 = 250 d SE F₁ = 450 d @ 80⁰ S of W Σ Fx -200 (West) 300(sin 35⁰) =-172 (West) 250(cos 45°) = +177 (East) 450(cos 80°) = -78.1 (West) 2. F₁ = 332 d @ 35⁰ W of N F2 = 420 d @ 75⁰ E of N F3 = 108 d SW -273 (West) Fy 0 300(cos 35°) =+246 (North) 45⁰ = -177 (South) 450(sin 80°) =-443 (South) -374 (South) Sketch F₁ = 200 d F₂=300 d FAY! F3-250 d 45⁰ F t 80⁰ 35⁰1 F2y F3v F4=150 d ANSWER NO. 2 ONLY
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The individual forces on the box below are as follows: Force A = 30 Newtons, Force B = 100 Newtons, Force C = 48 Newtons, and Force D = 100 Newtons. What is the net force on the box? ↑B Net Force = unit direction Select an answer
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