The one-to-one functions g and h are defined as follows. g= {(-3, -4), (2, 5), (5, -3), (7, -9)} (x)%3D2X+13 Find the following. 8 (-3) = 0 h %3D (a on")(-s) = 0 hoh

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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The one-to-one functions \( g \) and \( h \) are defined as follows:

\[
g = \{(-3, -4), (2, 5), (5, -3), (7, -9)\}
\]

\[
h(x) = 2x + 13
\]

**Find the following:**

1. \( g^{-1}(-3) = \)
2. \( h^{-1}(x) = \)
3. \( (h \circ h^{-1})(-3) = \)

**Explanation of Elements:**

- The function \( g \) is defined as a set of pairs, representing key values and their associated outputs.
- The function \( h(x) \) is expressed as a linear function with a slope of 2 and a y-intercept of 13.

You are tasked to find the inverse of these functions and compose them in specific ways to solve the given expressions.
Transcribed Image Text:The one-to-one functions \( g \) and \( h \) are defined as follows: \[ g = \{(-3, -4), (2, 5), (5, -3), (7, -9)\} \] \[ h(x) = 2x + 13 \] **Find the following:** 1. \( g^{-1}(-3) = \) 2. \( h^{-1}(x) = \) 3. \( (h \circ h^{-1})(-3) = \) **Explanation of Elements:** - The function \( g \) is defined as a set of pairs, representing key values and their associated outputs. - The function \( h(x) \) is expressed as a linear function with a slope of 2 and a y-intercept of 13. You are tasked to find the inverse of these functions and compose them in specific ways to solve the given expressions.
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