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the one dimensional array X contains the elements of array H(5,5) on row by row. Then print the array X into List Box. 1-...... 2-. K=K+1 3-... Next J, I 4-..... 5-..... Next I 1-For 1=1 To K 2-Blank 3-X(K) =H OJ) 4-For 1=1 To K 5-List1.AddItem str(x(1)) 1-For I=1 To 5 2-For J=1 To 5 3-H OJ) =X(K) 4-For I=1 To K 5- List1.AddItem str(X(1)) 1-For 1=1 To 5 2-For J=1 To 5 3-X OH (I,J) 4-For 1=1 To 5 5- List1.AddItem str(X(1))

the one dimensional array X contains the elements of array H(5,5) on row by row. Then print the array X into List Box. 1-...... 2-. K=K+1 3-... Next J, I 4-..... 5-..... Next I 1-For 1=1 To K 2-Blank 3-X(K) =H OJ) 4-For 1=1 To K 5-List1.AddItem str(x(1)) 1-For I=1 To 5 2-For J=1 To 5 3-H OJ) =X(K) 4-For I=1 To K 5- List1.AddItem str(X(1)) 1-For 1=1 To 5 2-For J=1 To 5 3-X OH (I,J) 4-For 1=1 To 5 5- List1.AddItem str(X(1))

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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This code segment create the one dimensional array X contains the elements of array H(5,5) on row by row. Then print the array X into List Box. 1-....... 2-..... K=K+1 3-....... Next J, I 4-...... 5-....... Next I 1-For 1=1 To K 2-Blank 3-X(K) =H (I, OJ) 4-For 1=1 To K 5-List1.AddItem str(x(1)) 1-For 1=1 To 5 2-For J=1 To 5 3-H (1, OJ) =X(K) 4-For I=1 To K 5- List1.AddItem str(X(1)) 1-For 1=1 To 5 2-For J=1 To 5 3-X(K) OH (1, J) 4-For 1=1 To 5 5- List1.AddItem str(X(1))
Transcribed Image Text:This code segment create the one dimensional array X contains the elements of array H(5,5) on row by row. Then print the array X into List Box. 1-....... 2-..... K=K+1 3-....... Next J, I 4-...... 5-....... Next I 1-For 1=1 To K 2-Blank 3-X(K) =H (I, OJ) 4-For 1=1 To K 5-List1.AddItem str(x(1)) 1-For 1=1 To 5 2-For J=1 To 5 3-H (1, OJ) =X(K) 4-For I=1 To K 5- List1.AddItem str(X(1)) 1-For 1=1 To 5 2-For J=1 To 5 3-X(K) OH (1, J) 4-For 1=1 To 5 5- List1.AddItem str(X(1))
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