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The one at pH 9.0 has a concentration of 10^-9 of H+, and the one at pH 10.0 has a concentration of 10^-10 H+. The concentration we want when they're mixed is 10^-9.4 H+. The total number of H+ ions we want in the 200 mL is 10^(-9.4) * 0.200L = 7.96 x 10-11 Now we write an equation for total volume and another for hydrogen ions: x + y = 0.200 L 10^(-9)*x+ 10^(-10)*y= 7.96 x 10-11 ions %3D Solving these simultaneously gives x = 0.13L and y = 0.07L

The one at pH 9.0 has a concentration of 10^-9 of H+, and the one at pH 10.0 has a concentration of 10^-10 H+. The concentration we want when they're mixed is 10^-9.4 H+. The total number of H+ ions we want in the 200 mL is 10^(-9.4) * 0.200L = 7.96 x 10-11 Now we write an equation for total volume and another for hydrogen ions: x + y = 0.200 L 10^(-9)*x+ 10^(-10)*y= 7.96 x 10-11 ions %3D Solving these simultaneously gives x = 0.13L and y = 0.07L

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.3QE: Sketch a titration curve for the titration of potassium hydroxide with HCl, both 0.100 M. Identify...
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The one at pH 9.0 has a concentration of 10^-9 of H+, and the one at pH 10.0 has a concentration of 10^-10 H+. The concentration we want when they're mixed is 10^-9.4 H+. The total number of H+ ions we want in the 200 mL is 10^(-9.4) * 0.200L = 7.96 x 10-11 Now we write an equation for total volume and another for hydrogen ions: x+y= 0.200 L 10^(-9)*x+ 10^(-10)*y = 7.96 x 10-11 ions %3D Solving these simultaneously gives x = 0.13L and y = 0.07L
Transcribed Image Text:The one at pH 9.0 has a concentration of 10^-9 of H+, and the one at pH 10.0 has a concentration of 10^-10 H+. The concentration we want when they're mixed is 10^-9.4 H+. The total number of H+ ions we want in the 200 mL is 10^(-9.4) * 0.200L = 7.96 x 10-11 Now we write an equation for total volume and another for hydrogen ions: x+y= 0.200 L 10^(-9)*x+ 10^(-10)*y = 7.96 x 10-11 ions %3D Solving these simultaneously gives x = 0.13L and y = 0.07L
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