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The one at pH 9.0 has a concentration of 10^-9 of H+, and the one at pH 10.0 has a concentration of 10^-10 H+. The concentration we want when they're mixed is 10^-9.4 H+. The total number of H+ ions we want in the 200 mL is 10^(-9.4) * 0.200L = 7.96 x 10-11 Now we write an equation for total volume and another for hydrogen ions: x + y = 0.200 L 10^(-9)*x+ 10^(-10)*y= 7.96 x 10-11 ions %3D Solving these simultaneously gives x = 0.13L and y = 0.07L

The one at pH 9.0 has a concentration of 10^-9 of H+, and the one at pH 10.0 has a concentration of 10^-10 H+. The concentration we want when they're mixed is 10^-9.4 H+. The total number of H+ ions we want in the 200 mL is 10^(-9.4) * 0.200L = 7.96 x 10-11 Now we write an equation for total volume and another for hydrogen ions: x + y = 0.200 L 10^(-9)*x+ 10^(-10)*y= 7.96 x 10-11 ions %3D Solving these simultaneously gives x = 0.13L and y = 0.07L

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The one at pH 9.0 has a concentration of 10^-9 of H+, and the one at pH 10.0 has a concentration of 10^-10 H+. The concentration we want when they're mixed is 10^-9.4 H+. The total number of H+ ions we want in the 200 mL is 10^(-9.4) * 0.200L = 7.96 x 10-11 Now we write an equation for total volume and another for hydrogen ions: x+y= 0.200 L 10^(-9)*x+ 10^(-10)*y = 7.96 x 10-11 ions %3D Solving these simultaneously gives x = 0.13L and y = 0.07L
Transcribed Image Text:The one at pH 9.0 has a concentration of 10^-9 of H+, and the one at pH 10.0 has a concentration of 10^-10 H+. The concentration we want when they're mixed is 10^-9.4 H+. The total number of H+ ions we want in the 200 mL is 10^(-9.4) * 0.200L = 7.96 x 10-11 Now we write an equation for total volume and another for hydrogen ions: x+y= 0.200 L 10^(-9)*x+ 10^(-10)*y = 7.96 x 10-11 ions %3D Solving these simultaneously gives x = 0.13L and y = 0.07L
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