The observed cell counts Off from the given contingency table, and estimated expected cell counts Bij are liste Low (0-3 hours) Moderate (4-19 hours) High (20-54 hours) 011 = 23 012 = 34 013 = 4 B12 = 30.5000 Ê13 = 7.2619 022 = 8 023 = 6 Ê, Secure Anxious = 23.2381 021- = 9 Ê₂ = 8.7619 21 22 = 11.5000 23 = 2.7381
The observed cell counts Off from the given contingency table, and estimated expected cell counts Bij are liste Low (0-3 hours) Moderate (4-19 hours) High (20-54 hours) 011 = 23 012 = 34 013 = 4 B12 = 30.5000 Ê13 = 7.2619 022 = 8 023 = 6 Ê, Secure Anxious = 23.2381 021- = 9 Ê₂ = 8.7619 21 22 = 11.5000 23 = 2.7381
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:The observed cell counts O, from the given contingency table, and estimated expected cell counts E, are listed in the table below.
.
Secure
x² =
Anxious
Low (0-3 hours)
011 = 23
(23-23.2381)2
23.2381
= 23.2381
021 = 9
Ê21 = 8.7619
(011-11)²+(012- - 812)²
B12
Now that we have found the estimated expected cell counts, we can calculate the chi-square test statistic X² for the test of independence. Substitute the
values of the observed and estimated expected cell counts from the table above into the formula, rounding the final answer to two decimal places.
Σ(0-12
+...
Moderate (4-19 hours) High (20-54 hours)
013 = 4
Ê13 = 7.2619
30.5000
12 = 34
Ê12 = 30.5000
- 30.5000
00) ²
022 = 8
Ê 22 = 11.5000
(023-823)²
023 = 6
Ê23 = 2.7381
+ +
(6-())²
2.7381
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