The observations below were collected at equal sampling intervals from a process with po- 20 and og=1 for the purpose of monitoring the process.Observation #i19.322.20.5518.14418.96(1) Construct a suitable CUSUM chart for monitoring the process if the mean of the process will shift to 19?(2) If the control limit of the CUSUM chart is reduced by log, the false alarm will:(a) increase(b) decrease©) remain the same(3) Is the process in control or out of control?

Given, Observations 1 19.32 2 20.55 3 18.14 4 18.96

Answered: The observations below were collected…

Practical Management Science

6th Edition

ISBN:9781337406659

Author:WINSTON, Wayne L.

Publisher:WINSTON, Wayne L.

Chapter2: Introduction To Spreadsheet Modeling

Section: Chapter Questions

Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...

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Aspen Plastics produces plastic bottles to customer order.The quality inspector randomly selects four bottles fromthe bottle machine and measures the outside diameter ofthe bottle neck, a critical quality dimension that determineswhether the bottle cap will fit properly. The dimensions(inch) from the last six samples are Assume that only these six samples are sufficient, and use thedata to determine control limits for an R- and an x-chart.
Lay's potato chip filling process has a lower specification limit of 9.5 oz. and an upper specification of 10.5 oz. The mean is 10 oz. What should be the value for standard deviation in this process to achieve a ppm of 5110? A. 0.1786 B. 0.2675 OC. 0.4453 OD. 0.3564
2) The specification for a Lindemann’s stainless steel chimney liner requires a thickness of 7.1 mm ± 0.1 mm. The firm’s quality analyst determines that the liner process operates at a mean thickness of 7.13 mm with the standard deviation of the process being 0.02 mm. a) Calculate the upper and the lower limits for the stainless steel chimney liner. b) Calculate the Cpand Cpkfor this process. Hint: Cp = (Upper Specification Limit – Lower Specification Limit)/6sigma Cpk = minimum of [(Upper Specification Limit – Xbar)/3sigma], [(Xbar – Lower Specification Limit)/3sigma]
Twelve samples, each containing five parts, were taken from a process that produces steel rods at Emmanual Kodzi's factory. The length of each rod in the samples was determined. The results were tabulated and sample means and ranges were computed. The results were: Sample Sample Mean (in.) Range (in.) Sample Sample Mean (in.) Range (in.) 1 9.602 0.033 7 9.603 0.041 2 9.602 0.041 8 9.605 0.034 3 9.593 0.034 9 9.597 0.027 4 9.606 0.051 10 9.601 0.029 5 9.599 0.031 11 9.603 0.039 6 9.599 0.036 12 9.606 0.047 Part 2 For the given data, the x double overbarx = 9.6013 inches (round your response to four decimal places). Part 3 Based on the sampling done, the control limits for 3-sigma x overbarx chart are: Upper Control Limit (UCL Subscript x…
A shirt manufacturer buys clothes by the 100-yard roll from a supplier. For setting a control chart to manage the irregularities (e.g., loose threads and tears), the following data were collected from a sample provided by the supplier. Sample 1 2 3 4 5 6 7 8 9 10 Irregularities 3 5 2 6 5 4 6 3 4 5 Which type of control chart should be used? Construct a control chart with two-sigma control limits. Suppose the next five rolls from the supplier had three, two, five, three, and seven irregularities. Is the supplier process under control? Explain and show work
A microbrewery tracks its output in gallons over a five hour period for each of seven days. Their data is in the table below, and they went ahead and calculated the averages and ranges for the individual samples and the overall averages Their data and the factors tables can be found below. Calculate the upper (LCL) and lower (UCL) control limits for X bar, and R charts for their process. Day (X values) X̅ R 1 46 49 45 47 48 47.0 4 2 43 52 46 52 44 47.4 9 3 45 55 46 51 43 48.0 12 4 39 44 42 43 40 41.6 5 5 45 50 48 50 42 47.0 8 6 44 48 45 45 40 44.4 8 7 41 44 52 50 47 46.8 11 X̿ = 46.03 R̅ 8.14 Xbar chart - LCL = 40.48, UCL=46.25, R chart LCL=0, UCL=14.01 Xbar chart - LCL = 44.21, UCL=48.41, R chart LCL=0.49, UCL=17.18 Xbar chart - LCL = 42.61, UCL=49.45, R chart LCL=0.65, UCL=15.63 Xbar chart - LCL = 44.21, UCL=51.62, R chart LCL=0, UCL=17.18 Xbar chart - LCL = 41.31, UCL=50.75, R chart LCL=0, UCL=17.18
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concernedas to whether caulking tubes are being properly capped. Ifa significant proportion of the tubes are not being sealed,Webster is placing its customers in a messy situation.Tubes are packaged in large boxes of 144. Several boxes areinspected, and the following numbers of leaking tubes arefound: Calculate p-chart three-sigma control limits to assesswhether the capping process is in statistical control.

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