The number of social media apps a person uses can be modeled by a discrete random variable X. Suppose thatX has the following probability distribution:4$%5AGADIrVtA. What is the probability that a person uses no social media apps?bogbOll6yhhpn&7OuX01P0.010.0220.090.150.210.180.1470.1080.069 0.0310 0.01j3456* 0083OILk(9OL)O1р[||?b:} The number of social media apps a person uses can be modeled by a discrete random variable X. Suppose thatX has the following probability distribution:4$%5AGADIrVtA. What is the probability that a person uses no social media apps?bogbOll6yhhpn&7OuX01P0.010.0220.090.150.210.180.1470.1080.069 0.0310 0.01j3456* 0083OILk(9OL)O1р[||?b:}

As per the Bartleby guildlines we have to solve first three subparts and rest can be…

Answered: The number of social media apps a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A certain disease has infected a particular region in South Africa. The most recent study conducted on the viral clearance or hospitalization days by this infection is given by the dataset below. Answer the questions that follows and express your final answer in three decimal places whenever possible. Hospitalization (Days) Frequency 3.0 4.8 6.5 1 8.2 10.0 a. Find the probability that a randomly selected patient is hospitalized for at most 8.2 days: b. Find the probability that a randomly selected patient is hospitalized for at least 8.2 days:
The mean height of women in a country (ages 20−29) is 63.6 inches. A random sample of 70 women in this age group is selected. What is the probability that the mean height for the sample is greater than 64 inches? Assume σ=2.79. The probability that the mean height for the sample is greater than 64 inches is _________.
In the probability distribution to the right, the random variable X represents the number of marriages an individual aged 15 years or older has been involved in. Compute and interpret the mean of the random variable X. Hx = marriages (Type an integer or a decimal. Do not round.) X 0 1 2 3 4 5 P(x) 0.264 0.567 0.136 0.029 0.003 0.001
Let X = {Email, In Person, Instant Message, Text Message}; P(Email) = 0.06 P(In Person) = 0.55 P(Instant Message) = 0.24 P(Text Message) = 0.15 Is this model a probability distribution? A. Yes. B. No. C. Maybe.
The annual rainfall (in inches) in a certain region is normally distributed with u = 24 and o O A. 0.117 4.2. What is the probability that the rainfall exceeds 29 inches in a given year? O B. 0.025 O C. 0.063 D. 0.125
A random sample of adults was asked about their highest education level completed. The distribution of results is shown in the table. What is the probability that the highest level of education of an adult is a high school diploma, given that they have completed at least one of the education levels shown? 0.04 0.16 0.47 0.84
Based on a Comcast survey, there is a 0.8 probability that a randomly selected adult will watch prime-time TV live, instead of online, on DVR, etc. Assume that seven adults are randomly selected. Find the probability that fewer than three of the selected adults watch prime-time live. OA. 0.00430 B. 0.000358 OC. 0.0512 O D. 0.00467
Assume that 12 jurors are randomly selected from a population in which 60% of the people are Mexican-Americans. Refer to the probability distribution table below and find the indicated probabilities. Number of Mexican-Americans Probability 0 0 1 0.0003 2 0.0025 3 0.0125 4 0.042 5 0.1009 6 0.1766 7 0.227 8 0.2128 9 0.1419 10 0.0639 11 0.0174 12 0.0022 a) Find the probability of at most 4 Mexican-Americans among 12 jurors. Give answer as a decimal. b) Find the probability of more than 4 Mexican-Americans among 12 jurors. Give answer as a decimal.
The mean height of women in a country (ages 20 −29) is 63.6 inches. A random sample of 55 women in this age group is selected. What is the probability that the mean height for the sample is greater than 64 inches? Assume σ= 2.65
Which answer is it?
The table below shows the results of a survey that asked 2853 people whether they are involved in any type of charity work. A person is selected at random from the sample. Complete parts (a) through (d). Occasionally Frequently 223 Not at all Total Male 453 793 1469 Female 205 430 749 1384 Total 428 883 1542 2853 (a) Find the probability that the person is frequently or occasionally involved in charity work. P(being frequently involved or being occasionally involved) = 0.460 (Round to the nearest thousandth as needed.) (b) Find the probability that the person is female or not involved in charity work at all. P(being female or not being involved) = (Round to the nearest thousandth as needed.)

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