Construct 98% confidence intervals for the a) population variance and the b)population standard deviation **Confidence Interval for Population Variance and Standard Deviation**The data represents the reserve capacity hours of 10 randomly selected automotive batteries:- 1.71, 1.87, 1.58, 1.61, 1.78- 1.98, 1.36, 1.58, 1.47, 2.05**Instructions:**Given that the sample is from a normally distributed population, we need to construct a 98% confidence interval for:(a) The population variance \(\sigma^2\)(b) The population standard deviation \(\sigma\)**Tasks:**(a) Determine the confidence interval for the population variance and fill in the blanks. Round answers to three decimal places as necessary.

Use STDEV function in excel to find the standard deviation. Then, s=0.2215. And the variance is…

The number of hours of reserve capacity of 10 randomly selected automotive batteries is shown to the right. 1.71 1.87 1.58 1.61 1.78 1.98 1.36 1.58 1.47 2.05 Assume the sample is taken from a normally distributed population. Construct 98% confidence intervals for (a) the population variance o2 and (b) the population standard deviation o. (a) The confidence interval for the population variance is ( ). (Round to three decimal places as needed.)

The number of hours of reserve capacity of 10 randomly selected automotive batteries is shown to the right. 1.71 1.87 1.58 1.61 1.78 1.98 1.36 1.58 1.47 2.05 Assume the sample is taken from a normally distributed population. Construct 98% confidence intervals for (a) the population variance o2 and (b) the population standard deviation o. (a) The confidence interval for the population variance is ( ). (Round to three decimal places as needed.)

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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