The null and alternative hypothesis in symbols would be: | Ho:µ < 69.76 H1:µ > 69.76 Ho:u > 69.76 H1 :µ < 69.76 Ho:p = 69.76 H1:p + 69.76 G0 76
The null and alternative hypothesis in symbols would be: | Ho:µ < 69.76 H1:µ > 69.76 Ho:u > 69.76 H1 :µ < 69.76 Ho:p = 69.76 H1:p + 69.76 G0 76
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![Suppose that BC financial aid alots a textbook
stipend by claiming that the average textbook at
BC bookstore costs $ 69.76. You want to test this
claim,
The null and alternative hypothesis in symbols
would be:
O Ho: µ < 69.76
H1:µ > 69.76
O Ho: µ 2 69.76
H1:µ < 69.76
O Ho:p = 69.76
H1:p # 69.76
O Ho: µ = 69.76
H1 :µ # 69.76
O Ho:p 2 69.76
H1:p < 69.76
O Ho:p < 69.76
H1:p > 69.76
The null hypothesis in words would be:
O The average price of textbooks in a sample
is $ 69.76
The average price of all textbooks from the
store is $ 69.76
The average of price of all textbooks from
the store is greater than $ 69.76.
O The average of price of all textbooks from
the store is less than $ 69.76.
O The proportion of all textbooks from the
store that are less than 69.76 is equal to
50%
Based on a sample of 100 textbooks at the store,
you find an average of 70.36 and a standard
deviation of 26.8.
The point estimate is:
(to 3 decimals)
The 95 % confidence interval (use z*) is:
to](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7f50d535-2628-4dc4-85fd-ea429775f729%2F43762ff6-07ef-4bb8-995a-bd8bb7e197f3%2Fi5nhzgq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Suppose that BC financial aid alots a textbook
stipend by claiming that the average textbook at
BC bookstore costs $ 69.76. You want to test this
claim,
The null and alternative hypothesis in symbols
would be:
O Ho: µ < 69.76
H1:µ > 69.76
O Ho: µ 2 69.76
H1:µ < 69.76
O Ho:p = 69.76
H1:p # 69.76
O Ho: µ = 69.76
H1 :µ # 69.76
O Ho:p 2 69.76
H1:p < 69.76
O Ho:p < 69.76
H1:p > 69.76
The null hypothesis in words would be:
O The average price of textbooks in a sample
is $ 69.76
The average price of all textbooks from the
store is $ 69.76
The average of price of all textbooks from
the store is greater than $ 69.76.
O The average of price of all textbooks from
the store is less than $ 69.76.
O The proportion of all textbooks from the
store that are less than 69.76 is equal to
50%
Based on a sample of 100 textbooks at the store,
you find an average of 70.36 and a standard
deviation of 26.8.
The point estimate is:
(to 3 decimals)
The 95 % confidence interval (use z*) is:
to
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