Suppose that BC financial aid alots a textbookstipend by claiming that the average textbook atBC bookstore costs $ 69.76. You want to test thisclaim,The null and alternative hypothesis in symbolswould be:O Ho: µ < 69.76H1:µ > 69.76O Ho: µ 2 69.76H1:µ < 69.76O Ho:p = 69.76H1:p # 69.76O Ho: µ = 69.76H1 :µ # 69.76O Ho:p 2 69.76H1:p < 69.76O Ho:p < 69.76H1:p > 69.76The null hypothesis in words would be:O The average price of textbooks in a sampleis $ 69.76The average price of all textbooks from thestore is $ 69.76The average of price of all textbooks fromthe store is greater than $ 69.76.O The average of price of all textbooks fromthe store is less than $ 69.76.O The proportion of all textbooks from thestore that are less than 69.76 is equal to50%Based on a sample of 100 textbooks at the store,you find an average of 70.36 and a standarddeviation of 26.8.The point estimate is:(to 3 decimals)The 95 % confidence interval (use z*) is:to

mu = 69.76 n = 100 xbar = 70.36 s =26.8

Answered: The null and alternative hypothesis in…

The null and alternative hypothesis in symbols would be: | Ho:µ < 69.76 H1:µ > 69.76 Ho:u > 69.76 H1 :µ < 69.76 Ho:p = 69.76 H1:p + 69.76 G0 76

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Apparently what I put was incorrect.
please find the test statistic find the p-value for the found test statistic round the p-value to the four decimal places as needed.
A popular theory is that presidential candidates have an advantage if they are taller than their main opponents. Listed are heights (in centimeters) of randomly selected presidents along with the heights of their main opponents. Complete parts (a) and (b) below. Height (cm) of President 185 170 179 191 194 179 9 Height (cm) of Main Opponent 170 184 174 166 194 182 Identify the test statistic. t= 0.57 (Round to two decimal places as needed.) Identify the P-value P-value = 0.286 (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is greater than the significance level, fail to reject the null hypothesis. There is not sufficient evidence to support the claim that presidents tend to be taller than their opponents. b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature of the confidence interval leads to the same conclusion reached in part (a)? The confidence interval…
K A company is developing a new high performance wax for cross country ski racing. In order to justify the price marketing wants, the wax needs to be very fast. Specifically, the mean time to finish their standard test course should be less than 55 seconds for a former Olympic champion. To test it, the champion will ski the course 8 times. The champion's times (selected at random) are 54.9, 63.7, 48.1, 53.9, 49.3, 47.4, 53.7, and 44.9 seconds to complete the test course. Should they market the wax? Assume the assumptions and conditions for appropriate hypothesis testing are met for the sample. Use 0.05 as the P-value cutoff level. Choose the correct null and alternative hypotheses below. Ο A. Ho:μ = 55 HAH55 Calculate the test statistic. ... t= OB. Ho:μ>55 HA:μ = 55 OD. Ho:μ<55 HAH=55 (Round to three decimal places as needed.) Calculate the P-value. P-value= (Round to four decimal places as needed.) Choose the correct clusion below. A. No, do not market the wax as there is insufficient…
The following table gives data for the velocity of a sports car accelerating from 0 to 193 miles per hour over the course of 36 seconds (10 thousandths of an hour).
Formulate the indicated conclusion in nontechnical terms. Be sure to address the original claim. The manufacturer of a refrigerator system for beer kegs produces refrigerators that are supposed to maintain a true mean temperature, . of 48"F, ideal for a certain type of German piluner The owner of the hrewery does not agree wth the refrigerator manufacturer, and claims he can prove that the true mean temperature is incorrect. Assuming that a hypothesis test of the claim has been conducted and that the conclusion is to reject the null hypothesis, state the conclusaon in nontechnical terms. O There is sufficient evidence to support the claim that the mean temperature is different from 4S'F. There is sufficient evidence to support the claim that the mean temperature is equal to 45F. O There is not sufficient evidence to support the claim that the mean temperature is equal to 45'F. O There is not sufficient evidence to support the claim that the mean temperature is different from 48°F.
Suppose X~N(186,19) and Z~N(0,1). If z = 1.24, what is it on an X scale? Express your answer to two decimal places (ex: 123.45).
Interpret a P-value: The manufacturer of a medication designed to lower blood pressure claims that the mean systolic blood pressure for people taking their medication is less than 135. To test this claim, blood pressure is measured for a sample of 500 people who are taking the medication. The P-value for testing Ho: μ = 135 versus H₁: µ< 135 is P = 0.001. a. The manufacturer concludes that because the P-value is very small, we can be fairly certain that the mean pressure is less than 135, but we cannot conclude that it is a lot smaller. Is this conclusion justified?
Referring to Table 2, the mean square for the factor filling time is____ 1). 0.9030 2). 0.4234 3). 0.4515 4). 0.2117
Use linear approximation to estimate the value of 28 /28 5.15 5.2 5.25 5.3
Solve for C) answer b was wrong
Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below. TInterval (13.046,22.15) X = 17.598 Sx = 16.01712719 n = 50 Click the icon to view a t distribution table. a. What is the number of degrees of freedom that should be used for finding the critical value t12? df = (Type a whole number.) b. Find the critical value t/2 corresponding to a 95% confidence level. ta12 = %3D (Round to two decimal places as needed.) c. Give a brief general description of the number of degrees of freedom. A. The number of degrees of freedom for a collection of sample data is the total number of sample values. B. The number of degrees of freedom for a collection of sample data is the number of sample values that can vary after certain restrictions have been imposed on all data values. C. The number of degrees of freedom for a collection of sample data is the number of sample values that are determined after certain restrictions…