**Half-Life Calculation of Oxygen Isotopes**This problem involves calculating the ratio of two isotopes of oxygen with distinct half-lives.**Given:**- The isotope \(\mathbf{{{}^{15}_{8}O}}\) has a half-life of 122.2 seconds.- The isotope \(\mathbf{{{}^{19}_{8}O}}\) has a half-life of 26.9 seconds.- Initially, a sample contains equal amounts of both isotopes.The task is to determine the ratio of \(\mathbf{{{}^{15}_{8}O}}\) to \(\mathbf{{{}^{19}_{8}O}}\) after 3.0 minutes.**Steps to Solve:**1. **Convert Time to Seconds:** - 3 minutes = 3 * 60 = 180 seconds2. **Calculate Number of Half-Lives:** - For \(\mathbf{{{}^{15}_{8}O}}\): \( \frac{180}{122.2} \approx 1.472 \text{ half-lives} \) - For \(\mathbf{{{}^{19}_{8}O}}\): \( \frac{180}{26.9} \approx 6.690 \text{ half-lives} \)3. **Exponential Decay Calculation:** - Remaining fraction of \(\mathbf{{{}^{15}_{8}O}}\): \( (0.5)^{1.472} \approx 0.351 \) - Remaining fraction of \(\mathbf{{{}^{19}_{8}O}}\): \( (0.5)^{6.690} \approx 0.01 \)4. **Calculate the Ratio:** - Ratio of \(\mathbf{{{}^{15}_{8}O}}\) to \(\mathbf{{{}^{19}_{8}O}}\) after 3.0 minutes: \( \frac{0.351}{0.01} \approx 35.1 \)Therefore, the ratio of \(\mathbf{{{}^{15}_{8}O}}\) to \(\mathbf{{{}^{19}_{8}O}}\) after 3.0 minutes is approximately \(\mathbf{35.1}\).**Conclusion:**After 3.0 minutes, for every 1 unit of \(\mathbf{{{}^{19}_{8}O}}\

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The nucleus (15 8) O has a half-life of 122.2 s; (19 8) O has a half-life of 26.9 s. Assume that at some time a sample contains equal amounts of both isotopes. What is the ratio of (15 8) O to (19 8) O after 3.0 minutes?