The npn transistor circuit of Figure 1 has VBE = 0.5 V and Bp = 80. Determine the value of R1 that gives Ic = 4 mA and the corresponding value of VCE- Rc 4 ΚΩ R1 C B Vcc Q1 20 V E R2 5 ΚΩ RE 200 2

Q: Figure 2 (for numbers 10 to 14). Vcc= 6V, RB =10k, RC=1k, B(beta)=100, hie=1k. Vcc O Vo A V₁O Zo'…

A: Given data Vcc=6V Rb=10k Rc=1k Beta=100

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Q: Ex: 7 Decide the transistor in below figure is in Saturation or not? Vce(sat)=0.2 V 3V Ra ww 10 k Rc…

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Q: A fixed bias n-channel JFET with Vdd= 12V, Rd= 1.2k ohms. Idss=12mA and Vp=-4V. Determine Id. O a.…

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Photoconductive Cell

Photoconductive cells are light-sensitive resistors in which resistance is inversely proportionated to light intensity when illuminated. These devices consist of a thin single-crystal or polycrystalline film of composite semiconductor materials. Cadmium sulfide (CdS) is used to make the most commercially available photoconductive particles which are sensitive to light in the visible spectrum. Other less commonly used substances respond to infrared light, but not to the visible spectrum. Such substances are lead sulfide (PbS), lead selenide (PbSe), and lead telluride (PbTe), and so on.