The normal time for this operation = 11 sec

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Suppose Charlene Brewster has times (in seconds) of 8.4, 8.6, 8.3, 8.5, 8.7, 8.5 and a performance rating of 110%.
The normal time for this operation = seconds (round your response to two decimal places).
Transcribed Image Text:Suppose Charlene Brewster has times (in seconds) of 8.4, 8.6, 8.3, 8.5, 8.7, 8.5 and a performance rating of 110%. The normal time for this operation = seconds (round your response to two decimal places).
Expert Solution
Calculation of Observed time

Observed time = Average of recorded times

= (8.4 + 8.6 + 8.3 + 8.5 + 8.7 + 8.5)/6

= 8.5 seconds

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