The normal (at 760 mmHg, or 1 atm) boling point of water is 100°C. What mass (g. 3 sig. figs) of glucose (CH2O) would you have to dissolve in 1000 g of water to decrease the vapor pressure at 100°C to 7524 mmHg? Assume that water follows Raoult's law. MH,O) 18.02 g/mol M(CH20-1802 g/mol Answer What is the normal boiling point of the solution in the previous question? (C 4 sig. figs) Assume ideal behavior. The ebulioscopic (boiling point elevation) constant of water is K-0512 kg/mol Answer

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter13: The Chemistry Of Solutes And Solutions
Section: Chapter Questions
Problem 111QRT: The organic salt [(C4H9)4N][ClO4] consists of the ions (C4H9)4N+ and ClO4. The salt dissolves in...
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The normal (at 760 mmHg, or 1 atm) boding point of water is 100°C. What mass (g. 3 sig. figs) of glucose (C6H12O) would you have to dissolve in 1000 g of water
to decrease the vapor pressure at 100°C to 752.4 mmHg? Assume that water follows Raoult's law. M(H₂O) = 18.02 g/mol M(CH₂O) = 180.2 g/mol.
Answer
What is the normal boiling point of the solution in the previous question? (C, 4 sig. figs.) Assume ideal behavior. The ebullioscopic (boiling point elevation) constant of
water is K-0.512 kg-*C/mol
Answer
Transcribed Image Text:The normal (at 760 mmHg, or 1 atm) boding point of water is 100°C. What mass (g. 3 sig. figs) of glucose (C6H12O) would you have to dissolve in 1000 g of water to decrease the vapor pressure at 100°C to 752.4 mmHg? Assume that water follows Raoult's law. M(H₂O) = 18.02 g/mol M(CH₂O) = 180.2 g/mol. Answer What is the normal boiling point of the solution in the previous question? (C, 4 sig. figs.) Assume ideal behavior. The ebullioscopic (boiling point elevation) constant of water is K-0.512 kg-*C/mol Answer
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