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The New York Mets sign a new player for $8,000,000 and his salary goes up by 3% every year. Initial value: 8.00,000 Growth factor: ,03 Equation: U- 8O0.OUD L.03)` A certain stock was worth $42 at the beginning of the day. Every hour the stock goes down by 15%. Initial value: 2 Growth factor: 15 y:42.6.15)* Equation:

The New York Mets sign a new player for $8,000,000 and his salary goes up by 3% every year. Initial value: 8.00,000 Growth factor: ,03 Equation: U- 8O0.OUD L.03)` A certain stock was worth $42 at the beginning of the day. Every hour the stock goes down by 15%. Initial value: 2 Growth factor: 15 y:42.6.15)* Equation:

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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4. The New York Mets sign a new player for $8,000,000 and his salary goes up by 3% every year. Initial value: 8,00,000 Growth factor:,03 Equation: U- 800.OU0 L.03) 5. A certain stock was worth $42 at the beginning of the day. Every hour the stock goes down by 15%. Initial value: 2 Growth factor: i15 Equation: y:42.6.15)*
Transcribed Image Text:4. The New York Mets sign a new player for $8,000,000 and his salary goes up by 3% every year. Initial value: 8,00,000 Growth factor:,03 Equation: U- 800.OU0 L.03) 5. A certain stock was worth $42 at the beginning of the day. Every hour the stock goes down by 15%. Initial value: 2 Growth factor: i15 Equation: y:42.6.15)*
b determines how fast the function increases or decreasing. For this reason, b is known as the growth factor. In the function: y = a(b)* , a is the y-intercept and b is the base factor that determines the direction of the graph and the steepness. In real-life situations we use x as time and try to find out how things change Because a is the y-intercept it plays a very important role in word problems involving exponential growth. a is exponentially over time. Some examples of this are money growing in a bank account by a certain percentage 5.1 Assignmar Exponential Growth and Decay Worksheet evely year or the population of a city growing by a certain percentage every year. funrowth factor is determined by starting with 100% and then adding or subtracting the percentage that the taker ir being increased by or subtracting the percentage that the function is being decreased by. Finally you tuke your growth factor as a percentage and change it into a decimal before plugging it into y = a(b)* na ihe initial value and growth factor for each of the situation below then plug them in to y = a(b)´ to get the function that models the problem. Answers are at the end. 1. You deposit $200 into a bank account. Every year that account increases by 12 %. [EXAMPLE] Initial value: 200 Growth factor: 1.12 Equation: y=200(1.12)* 2. The population of an apartment building is 4,000 people. Every month the population goes down by 12%. Initial value: 4000 Growth factor: 1.12 4: 4000 1.12) " Equation: 3. You start a bank account with $500 and the interest on the account is 8% every year. Initial value: 500 Growth factor: .08 Equation: y: 500 (.08)*
Transcribed Image Text:b determines how fast the function increases or decreasing. For this reason, b is known as the growth factor. In the function: y = a(b)* , a is the y-intercept and b is the base factor that determines the direction of the graph and the steepness. In real-life situations we use x as time and try to find out how things change Because a is the y-intercept it plays a very important role in word problems involving exponential growth. a is exponentially over time. Some examples of this are money growing in a bank account by a certain percentage 5.1 Assignmar Exponential Growth and Decay Worksheet evely year or the population of a city growing by a certain percentage every year. funrowth factor is determined by starting with 100% and then adding or subtracting the percentage that the taker ir being increased by or subtracting the percentage that the function is being decreased by. Finally you tuke your growth factor as a percentage and change it into a decimal before plugging it into y = a(b)* na ihe initial value and growth factor for each of the situation below then plug them in to y = a(b)´ to get the function that models the problem. Answers are at the end. 1. You deposit $200 into a bank account. Every year that account increases by 12 %. [EXAMPLE] Initial value: 200 Growth factor: 1.12 Equation: y=200(1.12)* 2. The population of an apartment building is 4,000 people. Every month the population goes down by 12%. Initial value: 4000 Growth factor: 1.12 4: 4000 1.12) " Equation: 3. You start a bank account with $500 and the interest on the account is 8% every year. Initial value: 500 Growth factor: .08 Equation: y: 500 (.08)*
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