The new operator is used to reserve a number of bytes in the stack of the virtual address space of a program

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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**Question: (2 points)**

The `new` operator is used to reserve a number of bytes in the stack of the virtual address space of a program.

- ○ True
- ○ False

**Explanation:**

The `new` operator in programming is typically used to allocate memory on the heap, not the stack, in the virtual address space of a program. Memory allocation on the stack is usually automatic and managed by the program's call stack, while dynamic memory allocation for objects or arrays is handled using the `new` operator for the heap. Therefore, the above statement is "False."
Transcribed Image Text:**Question: (2 points)** The `new` operator is used to reserve a number of bytes in the stack of the virtual address space of a program. - ○ True - ○ False **Explanation:** The `new` operator in programming is typically used to allocate memory on the heap, not the stack, in the virtual address space of a program. Memory allocation on the stack is usually automatic and managed by the program's call stack, while dynamic memory allocation for objects or arrays is handled using the `new` operator for the heap. Therefore, the above statement is "False."
**Code Analysis and Conceptual Question**

In the following code segment, the statement is made: "y is a local variable of the function half()." 

```cpp
void half(int& y)
{
    y /= 2;
}
```

**Question:**

- Is the statement "y is a local variable of the function half()" true or false?

Options:
- True
- False

**Explanation:**

The code provided defines a function named `half` which takes an integer reference `y` as its parameter. The operation `y /= 2;` divides the value of `y` by 2. In this context, `y` is not a typical local variable because it is a reference to an existing variable passed by the caller, meaning that changes to `y` within the function will affect the original variable. Thus, `y` acts more like an alias for the variable it references rather than being a local variable defined strictly within the function.
Transcribed Image Text:**Code Analysis and Conceptual Question** In the following code segment, the statement is made: "y is a local variable of the function half()." ```cpp void half(int& y) { y /= 2; } ``` **Question:** - Is the statement "y is a local variable of the function half()" true or false? Options: - True - False **Explanation:** The code provided defines a function named `half` which takes an integer reference `y` as its parameter. The operation `y /= 2;` divides the value of `y` by 2. In this context, `y` is not a typical local variable because it is a reference to an existing variable passed by the caller, meaning that changes to `y` within the function will affect the original variable. Thus, `y` acts more like an alias for the variable it references rather than being a local variable defined strictly within the function.
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