The new equation is cos 20- cos 0 = Notice that the quadratic formula can be applied to this equation. 49 Use the quadratic formula to find the value of cos 0. Remember that cos 0 must be negative. 2 cos 0 7 (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Based on the Image, I am unsure how to apply the quadratic formula to result in:

cosθ = - 2/7

an explanation would be appreciated.

(More information can be posted if needed) 

**Quadratic Equation and Cosine**

The new equation is \( \cos^2 \theta - \cos \theta = \frac{18}{49} \). Notice that the quadratic formula can be applied to this equation.

Use the quadratic formula to find the value of \( \cos \theta \). Remember that \( \cos \theta \) must be negative.

\[ \cos \theta = -\frac{2}{7} \]

(Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)
Transcribed Image Text:**Quadratic Equation and Cosine** The new equation is \( \cos^2 \theta - \cos \theta = \frac{18}{49} \). Notice that the quadratic formula can be applied to this equation. Use the quadratic formula to find the value of \( \cos \theta \). Remember that \( \cos \theta \) must be negative. \[ \cos \theta = -\frac{2}{7} \] (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)
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