The neutralization reaction of HCIO4 (strong acid) with NaOH is given below. HCIO4 (aq) + NaOH(aq) - H₂0 (1)+ NaCIC 128.1 ml of 0.649 M HCIO4 is combined with 128.1 ml of 0.649 M NaOH in a perfect calorimeter. Both of the st complete the final temperature of the solution in the calorimeter is 39.16. (You may assume that the specific h solution is 1.00 g/ml.) Calculate the enthalpy of neutralization (AH) for the reaction shown above (in kJ). kj ΔΗ

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**Neutralization Reaction of HClO₄ with NaOH**

The neutralization reaction of HClO₄ (a strong acid) with NaOH is presented below:

\[ \text{HClO}_4 \, (\text{aq}) + \text{NaOH} \, (\text{aq}) \rightarrow \text{H}_2\text{O} \, (\text{l}) + \text{NaClO}_4 \, (\text{aq}) \]
\[ \Delta H = ? \]

**Experiment Setup:**

- 128.1 ml of 0.649 M HClO₄ is combined with 128.1 ml of 0.649 M NaOH in a perfect calorimeter.
- Both starting solutions have an initial temperature of 34.73 °C.
- After the reaction, the final temperature of the solution in the calorimeter is 39.16 °C.

**Assumptions:**
- The specific heats of all solutions are the same as that of pure water.
- The density of each solution is 1.00 g/mL.

**Task:**

Calculate the enthalpy of neutralization \( \Delta H \) for the reaction shown above (in kJ).

\[ \Delta H = \underline{\ \ \ \ \ \ \ \ \ } \text{kJ} \]

**Instructions:**

1. **Check:** Use the information provided and perform the necessary calculations to find \( \Delta H \).
Transcribed Image Text:**Neutralization Reaction of HClO₄ with NaOH** The neutralization reaction of HClO₄ (a strong acid) with NaOH is presented below: \[ \text{HClO}_4 \, (\text{aq}) + \text{NaOH} \, (\text{aq}) \rightarrow \text{H}_2\text{O} \, (\text{l}) + \text{NaClO}_4 \, (\text{aq}) \] \[ \Delta H = ? \] **Experiment Setup:** - 128.1 ml of 0.649 M HClO₄ is combined with 128.1 ml of 0.649 M NaOH in a perfect calorimeter. - Both starting solutions have an initial temperature of 34.73 °C. - After the reaction, the final temperature of the solution in the calorimeter is 39.16 °C. **Assumptions:** - The specific heats of all solutions are the same as that of pure water. - The density of each solution is 1.00 g/mL. **Task:** Calculate the enthalpy of neutralization \( \Delta H \) for the reaction shown above (in kJ). \[ \Delta H = \underline{\ \ \ \ \ \ \ \ \ } \text{kJ} \] **Instructions:** 1. **Check:** Use the information provided and perform the necessary calculations to find \( \Delta H \).
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