the network of Fig. 9.80: Determine re. Find Aid = Vo/Vị- Calculate Zj. Determine fL fLe and fLe Determine the low cutoff frequency. Sketch the asymptotes of the Bode plot defined by the cutoff frequencies of part (d Sketch the low-frequency response for the amplifier using the results of part (e). 14 V = 5 pF Che = 12 pF Cwi %3! Cw. = 8 pF Che = 40 pF Cee = 8 pF 5.6 k2 68 kN 0.47 µF B = 120 %3D 0.47 µF 3.3 k2 10 k2 1.2 k2. 20 uF 0.47 μF FIG. 9.80

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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. Determine fLS , fLC, and fLE . e. Determine the low cutoff frequency. f. Sketch the asymptotes of the Bode plot defined by the cutoff frequencies of part (d). g. Sketch the low-frequency response for the amplifier using the results of part (e).
-Frequency Response-BJT Amplifier with R.
beat the analysis of Example 9.11 with r, = 40 kN. What is the effect on A, fLo
the resulting cutoff frequency?
mid'
the network of Fig. 9.80:
Determine r..
Find A,ia = Vo/Vị-
Calculate Z¡.
Determine fL fle and fLr-
Determine the low cutoff frequency.
Sketch the asymptotes of the Bode plot defined by the cutoff frequencies of part (d
Sketch the low-frequency response for the amplifier using the results of part (e).
mid
14 V
= 5 pF Che = 12 pF
Cwi
%3D
Cwo
= 8 pF Che = 40 pF
%3D
%3D
Cce = 8 pF
5.6 kN
68 kN
0.47 µF
Vo
B = 120
0.47 µF
3.3 k2
10 k2
1.2 k2.
20 μF
0.47 µF
FIG. 9.80
Problems 15, 19, 27, and 38.
Transcribed Image Text:-Frequency Response-BJT Amplifier with R. beat the analysis of Example 9.11 with r, = 40 kN. What is the effect on A, fLo the resulting cutoff frequency? mid' the network of Fig. 9.80: Determine r.. Find A,ia = Vo/Vị- Calculate Z¡. Determine fL fle and fLr- Determine the low cutoff frequency. Sketch the asymptotes of the Bode plot defined by the cutoff frequencies of part (d Sketch the low-frequency response for the amplifier using the results of part (e). mid 14 V = 5 pF Che = 12 pF Cwi %3D Cwo = 8 pF Che = 40 pF %3D %3D Cce = 8 pF 5.6 kN 68 kN 0.47 µF Vo B = 120 0.47 µF 3.3 k2 10 k2 1.2 k2. 20 μF 0.47 µF FIG. 9.80 Problems 15, 19, 27, and 38.
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