The motor turns gear A with a constant angular acceleration, a=4 rad/s², starting from rest. TA=71, rB=230, rD=121 The cord is wrapped around pulley D which is rigidly attached to gear B. LA TA D тав Find the distance of cylinder C in mm that it travels it t=2.4 sec. Give your answer as an integer.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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### Problem Description

The motor turns gear A with a constant angular acceleration, \(\alpha = 4 \, \text{rad/s}^2\), starting from rest.

Given:
- Radius of gear A, \(r_A = 71 \, \text{mm}\)
- Radius of gear B, \(r_B = 230 \, \text{mm}\)
- Radius of pulley D, \(r_D = 121 \, \text{mm}\)

The cord is wrapped around pulley D, which is rigidly attached to gear B.

### Diagram Explanation

The provided diagram shows:
- Gear A on the left with a radius \(r_A\)
- Gear B on the right with a larger radius \(r_B\)
- Pulley D, which is rigidly attached to gear B, with radius \(r_D\)
- A cord wrapped around pulley D
- A cylinder C hanging from the cord

### Problem

Find the distance (in mm) that cylinder C travels after \(t = 2.4 \, \text{seconds}\). Provide the answer as an integer.

### Solution

To find the distance, we need to calculate the linear displacement of the cord, which will be equal to the linear distance the cylinder C travels.

1. **Angular Displacement Calculation for Gear A:**
   - Gear A has a constant angular acceleration and starts from rest.
   - Use the formula for angular displacement:
     \[
     \theta_A = \frac{1}{2} \alpha t^2
     \]
     Given \(\alpha_A = 4 \, \text{rad/s}^2\) and \(t = 2.4 \, \text{s}\):
     \[
     \theta_A = \frac{1}{2} \times 4 \times (2.4)^2 
     \]
     \[
     \theta_A = \frac{1}{2} \times 4 \times 5.76 
     \]
     \[
     \theta_A = 11.52 \, \text{rad}
     \]

2. **Angular Velocity Relation Between Gears:**
   - Gears A and B are meshed, hence their tangential velocities are equal:
     \[
     r_A \omega_A = r_B \omega_B
     \]
     Since \(\omega\) is proportional to \(\theta
Transcribed Image Text:### Problem Description The motor turns gear A with a constant angular acceleration, \(\alpha = 4 \, \text{rad/s}^2\), starting from rest. Given: - Radius of gear A, \(r_A = 71 \, \text{mm}\) - Radius of gear B, \(r_B = 230 \, \text{mm}\) - Radius of pulley D, \(r_D = 121 \, \text{mm}\) The cord is wrapped around pulley D, which is rigidly attached to gear B. ### Diagram Explanation The provided diagram shows: - Gear A on the left with a radius \(r_A\) - Gear B on the right with a larger radius \(r_B\) - Pulley D, which is rigidly attached to gear B, with radius \(r_D\) - A cord wrapped around pulley D - A cylinder C hanging from the cord ### Problem Find the distance (in mm) that cylinder C travels after \(t = 2.4 \, \text{seconds}\). Provide the answer as an integer. ### Solution To find the distance, we need to calculate the linear displacement of the cord, which will be equal to the linear distance the cylinder C travels. 1. **Angular Displacement Calculation for Gear A:** - Gear A has a constant angular acceleration and starts from rest. - Use the formula for angular displacement: \[ \theta_A = \frac{1}{2} \alpha t^2 \] Given \(\alpha_A = 4 \, \text{rad/s}^2\) and \(t = 2.4 \, \text{s}\): \[ \theta_A = \frac{1}{2} \times 4 \times (2.4)^2 \] \[ \theta_A = \frac{1}{2} \times 4 \times 5.76 \] \[ \theta_A = 11.52 \, \text{rad} \] 2. **Angular Velocity Relation Between Gears:** - Gears A and B are meshed, hence their tangential velocities are equal: \[ r_A \omega_A = r_B \omega_B \] Since \(\omega\) is proportional to \(\theta
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