The motor exerts a force F on the 40.5-kg crate as shown in the graph. When t = 0, the crate is moving downward at 10 m/s. FIN) 450 150 (s) Part A Determine the velocity of the crate when t = 3s. Express your answer to three significant figures and include the appropriate units. Enter positive value if the velocity is directed upward and negative value if the velocity is directed downward. v = Part B Determine the velocity of the crate when t = 6 s. Express your answer to three significant figures and include the appropriate units. Enter positive value if the velocity is directed upward and negative value if the velocity is directed downward.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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The motor exerts a force F on the 40.5-kg crate as shown in the graph. When t = 0, the crate is moving downward at 10 m/s.
F (N)
450
B
150
t(s)
6.
Part A
Determine the velocity of the crate when t = 3 s.
Express your answer to three significant figures and include the appropriate units. Enter positive value if the velocity is directed upward and negative value if the velocity is directed downward.
Part B
Determine the velocity of the crate when t = 6 s.
Express your answer to three significant figures and include the appropriate units. Enter positive value if the velocity is directed upward and negative value if the velocity is directed downward.
v =
Transcribed Image Text:The motor exerts a force F on the 40.5-kg crate as shown in the graph. When t = 0, the crate is moving downward at 10 m/s. F (N) 450 B 150 t(s) 6. Part A Determine the velocity of the crate when t = 3 s. Express your answer to three significant figures and include the appropriate units. Enter positive value if the velocity is directed upward and negative value if the velocity is directed downward. Part B Determine the velocity of the crate when t = 6 s. Express your answer to three significant figures and include the appropriate units. Enter positive value if the velocity is directed upward and negative value if the velocity is directed downward. v =
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