The motion of a point P with respect to a Cartesian coordinate system is described by 7 = (2√tî + (4 ln(t + 1) + 2t²) 3) ft where t denotes time, t> 0, and is expressed in seconds. Determine the average acceleration of P between times t₁ =4 s and t2 = 6 s and find the difference between it and the true acceleration of Pat t= 5.1 s. (Round the final answers to four decimal places, Include a minus sign if necessary.) The average acceleration of Pis a = 13) ft/s². =( The difference between the average acceleration and the true acceleration of Pis a avg - a (5.1 s) ft/s².
The motion of a point P with respect to a Cartesian coordinate system is described by 7 = (2√tî + (4 ln(t + 1) + 2t²) 3) ft where t denotes time, t> 0, and is expressed in seconds. Determine the average acceleration of P between times t₁ =4 s and t2 = 6 s and find the difference between it and the true acceleration of Pat t= 5.1 s. (Round the final answers to four decimal places, Include a minus sign if necessary.) The average acceleration of Pis a = 13) ft/s². =( The difference between the average acceleration and the true acceleration of Pis a avg - a (5.1 s) ft/s².
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:The motion of a point P with respect to a Cartesian coordinate system is described by
7 = (2√tî + (4 ln(t + 1) + 2t²) 3) ft
where t denotes time, t> 0, and is expressed in seconds.
Determine the average acceleration of P between times t₁ = 4 s and t2 = 6 s and find the difference between it and the true
acceleration of Pat t = 5.1 s. (Round the final answers to four decimal places, Include a minus sign if necessary.)
X
Ĵ) ft/s².
avg
The difference between the average acceleration and the true acceleration of Pis a a (5.1 s) = (
ft/s².
→
The average acceleration of Pis a =
+
-
+
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