The most distant quasar is "JO313-1806". Its redshift is z = 7.64. [ z = (femitted - fobserved)/ fobserved] Assume that the redshift is due to relative motion. Then how fast is the quasar moving away from Earth? (speed as the fraction of c = ) .704

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**The Most Distant Quasar: J0313-1806**

1. **Redshift Details**  
   - The quasar "J0313-1806" has a redshift of \( z = 7.64 \).
   - Redshift formula: 
     \[
     z \equiv \frac{(f_{\text{emitted}} - f_{\text{observed}})}{f_{\text{observed}}}
     \]
   - Question: Assuming the redshift is due to relative motion, how fast is the quasar moving away from Earth?  
     - **Speed as a fraction of \( c \) (speed of light):** \( \frac{7.64}{\square} \)

2. **Hubble's Law and Distance Calculation**  
   - Hubble's Law states that the distance \( r \) depends on the speed of recession \( v \):
     \[
     v = H_0 r
     \]
   - Hubble constant \( H_0 \approx \frac{20 \text{ km/s}}{\text{Mly}} \).
   - Question: How many years are required for light to travel from the quasar to Earth?
     - **Years =** \( \square \)

Please fill in the boxes with the appropriate calculations to solve the questions.
Transcribed Image Text:**The Most Distant Quasar: J0313-1806** 1. **Redshift Details** - The quasar "J0313-1806" has a redshift of \( z = 7.64 \). - Redshift formula: \[ z \equiv \frac{(f_{\text{emitted}} - f_{\text{observed}})}{f_{\text{observed}}} \] - Question: Assuming the redshift is due to relative motion, how fast is the quasar moving away from Earth? - **Speed as a fraction of \( c \) (speed of light):** \( \frac{7.64}{\square} \) 2. **Hubble's Law and Distance Calculation** - Hubble's Law states that the distance \( r \) depends on the speed of recession \( v \): \[ v = H_0 r \] - Hubble constant \( H_0 \approx \frac{20 \text{ km/s}}{\text{Mly}} \). - Question: How many years are required for light to travel from the quasar to Earth? - **Years =** \( \square \) Please fill in the boxes with the appropriate calculations to solve the questions.
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