(Q53) A solution is prepared this is 1.38 x 104 M in magnesium nitrate and 1.76 x 104 M in sodiumfluoride at the moment of mixing. If, by chance, a precipitate were to form, it would have a Ksp valueof 5.16 x 1011. Given this information, will a precipitate form?Yes, because Q = 6.65 x 10-8O Yes, because Q = 4.27 x 10-12Both sodium nitrate and magnesium fluoride will precipitate out of solutionO No, because Q = 4.27 x 10-12O No, because Q = 6.65 x 10-8

Given, Molarity of Mg(NO3)2 = 1.38×10-4 M Molarity of NaF = 1.76 ×10-4 M Solubility equilibrium…

the moment of mixing. If, by chance, a pre 10-11. Given this information, will a precipi cause Q = 6.65 x 10-8 cause Q = 4.27 x 10-12 dium nitrate and magnesium fluoride will precipi ause Q = 4.27 x 10-12 ause Q = 6.65 x 10-8

the moment of mixing. If, by chance, a pre 10-11. Given this information, will a precipi cause Q = 6.65 x 10-8 cause Q = 4.27 x 10-12 dium nitrate and magnesium fluoride will precipi ause Q = 4.27 x 10-12 ause Q = 6.65 x 10-8

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

None
Ksp for BaCrO4 is 1.17x10^-10
I Review I Constant When a mixture of 10.5 g of acetylene (C,H2) and 10.5 g of oxygen (O2) is ignited, the resultant combustion reaction produces CO2 and H20. Part A Write the balanced chemical equation for this reaction. Express your answer as a balanced chemical equation. Identify all of the phases in your answer. ΑΣφ ? |2C, Н, + 50, >4CO, + 2H, О DA chemical reaction does not occur for this question. Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Part B Which is the limiting reactant? Express your answer as a chemical formula. O2 Submit Previous Answers v Correct
What is the equilibrium concentration of N₂ in water that is in contact with air at 25 °C and air pressure 1 atm? The mole fraction of N2₂ in the air is 80 %, and Henry's law constant for N₂ is 6 x 10-4 mol L-1 atm-1. Select the nearest value. O 4.8x 10-3 mg L-1 4.8 x 10-4 mmol L-1 0.6 x 10-4 mol L-1 6 x 10-3 g L-1 6 x 10-4 mol L-1
34. Calculate the standard enthalpy change (AH) at 298 K for the reaction of X&Y18 with O2. 2 XBY18+21 O2→8 XO +8 XO2 +18 Y,0 Reaction AH at 298 K 2 XgY18+25 O2 16 XO, + 18 Y O -11020 kJ 2 XO +O2 XO -566.0 kJ 210454 kJ 18756 J 0 13284 J D 1E5
Ksp= 3.00 x 10^-17
Portfolio V (6-10)
For the following reactions, predict whether the mole fraction of the reactants or products increases or remains the same when the volume of the reaction vessel is increased. SO2 (9) + 1/2 0, (9) = SO3 (g) а. mole fraction of reactants increases mole fraction of products increases mole fraction remains the same 2 CH4 (g) = C2H2 (g) + 3 H2 (g) b. mole fraction of reactants increases mole fraction of products increases Omole fraction remains the same N2 (9) + 2 O2 (9)=2 NO2 (g) с. mole fraction of reactants increases mole fraction of products increases Omole fraction remains the same
Calculate the solubility at 25 °C of CuBr in pure water and in a 0.0120M CoBr, solution. You'll find K's data in the ALEKS Data tab. sp Round both of your answers to 2 significant digits. 마을 solubility in 0.0120 M CoBr2 solution: ㅁ solubility in pure water: x10 ㅁㅁ 몸 Fraction
Part G Pt(s) |O₂(g) H+ (aq)||OH(aq) |O₂(g) Pt(s) Express your answer as a net ion equation. Identify all of the phases in your answer. Part H | ΑΣΦ A chemical reaction does not occur for this question. Submit Request Answer cell Calculate Ecell for the reaction in part G. Express your answer to three decimal places and include the appropriate units. HA ? Value Units ?
Consider the following reaction: 2HCl(aq)+Sr(OH)2(aq) → 2H2O(l)+SrCl2(aq) Enter the complete ionic equation for this reaction. Express your answer as a complete ionic equation. Identify all of the phases in your answer.