The molar solubility of *zinc carbonate* in a *0.269 M zinc nitrate* solution is [______] M. The problem statement is as follows:"The maximum amount of **lead hydroxide** that will dissolve in a **0.109 M lead acetate** solution is [ ] M."This statement is presented in the format of a fill-in-the-blank question, likely for educational purposes. The aim is to calculate or identify the solubility of lead hydroxide in the given concentration of lead acetate solution. There are no graphs or diagrams accompanying this text.

Note - Since you have asked multiple questions, we are supposed to solve only the first question for you. To get any particular question solved, please specify that question or repost that question only. 1. The molarity of zinc nitrate = 0.269 M The Ksp of zinc carbonate is 1.5 x 10-10 .Zinc nitrate is a strong electrolyte. So, it dissociates completely into Zn2+ and NO3- ions. Thus, [Zn2+] = [Zn(NO3)2] = 0.269 M Thus, the ICE table for the dissociation of ZnCO3 can be given as : ZnCO3(s) ⇌ Zn2+(aq) + CO32-(aq)Initial concentration (In M) 0.269 0Change +s sAt equilibrium (0.269+s) s Here s is the molar solubility.Now, the expression for Ksp can be given as : Ksp=Zn2+CO32-1.5×10-10=0.269+ssPutting 0.269+s≈0.269 since s is very small, we get :1.5×10-10=0.269ss=1.5×10-100.269⇒5.58×10-10MTherefore, the molar solubility of zinc carbonate in 0,269 M zinc nitrate solution is 5.58×10-10M.

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The molar solubility of zinc carbonate in a 0.269 M zinc nitrate solution is М.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

The molar solubility of *zinc carbonate* in a *0.269 M zinc nitrate* solution is [______] M.

The problem statement is as follows:

"The maximum amount of **lead hydroxide** that will dissolve in a **0.109 M lead acetate** solution is [ ] M."

This statement is presented in the format of a fill-in-the-blank question, likely for educational purposes. The aim is to calculate or identify the solubility of lead hydroxide in the given concentration of lead acetate solution. There are no graphs or diagrams accompanying this text.

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