The molar mass of nicotine is 162.1 g/mol. It contains 74.0 % carbon, 8.7 % hydrogen, and 17.3 % nitrogen. Determine nicotine’s empirical formula and molecular formula. Phenyl magnesium bromide is used as a Grignard reagent in organic synthesis. Determine its empirical and molecular formula if its molar mass is 181.313 g/mol and it contains 39.7458 % C, 2.77956 % H, 13.4050 % Mg, and 44.0697 % Br.

The molar mass of nicotine is 162.1 g/mol. It contains 74.0 % carbon, 8.7 % hydrogen, and 17.3 % nitrogen. Determine nicotine’s empirical formula and molecular formula. Phenyl magnesium bromide is used as a Grignard reagent in organic synthesis. Determine its empirical and molecular formula if its molar mass is 181.313 g/mol and it contains 39.7458 % C, 2.77956 % H, 13.4050 % Mg, and 44.0697 % Br.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: A compound contains only carbon, hydrogen, nitrogen, and sulphur. A combustion analyzer collects…

A: Given, A compound contains only carbon hydrogen, nitrogen and sulpur. The combustion analyzer…

Q: Acetaminophen has a elemental composition of 63.56% carbon, 6.00% hydrogen, 9.27% nitrogen and…

A: Step 1: carbon elemental composition /12, hydrogen composition /1, nitrogen composition /14, oxygen…

Q: When 1.615 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 5.545 grams…

A: The molecular formula is a formula generated from molecules that represents the total number of…

Q: Combustion analysis of a hydrocarbon produced 33.01 g CO2 and 13.51 g H2O. Calculate the empirical…

A: Solution Given data, The amount of CO2 = 33.01g The amount of H2O = 13.52g Number of moles of…

Q: Determine the empirical formula of a compound having the following elemental analysis: 52.2% C;…

A: "Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: What is the empirical formula of a compound that contains 63.25% Xe and 36.66%F by mass?

A: Empirical formula :- The simplest formula which shows only relative number of different atoms…

Q: When 2.115 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 6.637 grams…

A: First of all we calculate the mass of Carbon in Carbon dioxide and mass of Hydrogen in water. Then…

Q: The mineral perovskite is an excellent source for titanium. It is made up of 29.4%Ca, 35.2%Ti, and…

Q: When 3.433 grams of a hydrocarbon, C,Hy, were burnec in a combustion analysis apparatus, 10.52 grams…

A: Mass of Hydrocarbon = 3.433 grams Molar mass of Hydrocarbon = 86.18 grams Number of moles of…

Q: 0 g of a pure hydrocarbon was combusted in oxygen. The reaction was a complete combustion. This…

A: Hydrocarbons are the compounds of carbon and hydrogen only. On combustion, hydrocarbons produce…

Q: A compound contains carbon, hydrogen, and sulphur. A combustion analyzer collects 45.0 g of CO2,…

Q: Combustion analysis of a hydrocarbon produced 33.01 g CO2 and 4.83 g H2O. Calculate the empirical…

A: Given : Mass of CO2 produced = 33.01 g Mass of H2O produced = 4.83 g And the compound is…

Q: Determine the molecular formula of the compound with an empirical formula of CH and a molar mass of…

A: Given:- Determine the molecular formula of the compound with an empirical formula of CH and a molar…

Q: Determine the empirical formula of the compound according to its elemental analysis: 38.13% C by…

Q: When 4.993 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 15.67 grams…

Q: Catnip's mass composition is 72.3% C, 8.4% H, and 19.3% O). Its molar mass is 166.2 g/mol. Deduce…

A: Empirical Formula :- It is the simplest ratio of number if atoms present in a molecule. Molecular…

Q: common organic solvent, gives 7.62 mgmg of CO2CO2 and 1.78 mgmg of H2OH2O. If the compound contains…

Q: What is the empirical formula of a compound that contains 72.46% carbon, 6.09% hydrogen, and the…

Q: What is the molecular formula of a compound

A: Given :- molar mass of compound = 220 g/mol Empirical formula = P2O3. To find :…

Q: Part D. A 28.50 g sample of a compound of carbon, sulfur, hydrogen, and combusted (burned). 35.25 g…

Q: Determine molecular formula. An organic compound that only contains C, H, and O was subjected to…

A: Since the compound is made up of only C, H and O. Hence we can assume the empirical formula of…

Q: a compound contains only hydrogen, carbon, and oxygen. combustion of 10.68mg of the compound…

A: The combustion reaction of given compound and its masses are shown below,

Q: Chemical analysis of a asprin tablet determined that it was composed of 57.7% carbon, 37.5% oxygen…

Q: When 5.555 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 17.43 grams…

Q: A compound is 7.7% (by mass) hydrogen and 92.7 % carbon. It has a molecular weight of 52 g/mole.…

A: Empirical formula are the formula which represent simplest ratio of an element present in a given…

Q: The mass percentages of H and O in a compound used for bleaching are 5.9% H and 94.1% O. The molar…

A: Molecular formula: In a molecular formula we describe the number of atoms of all the elements…

Q: Combustion analysis of naphthalene, a hydrocarbon used in mothballs, produces 8.80 g CO2 and 1.44 g…

A: The ratio of the given mass to the molar mass is known as the number of moles. Mathematically,

Q: Combustion of 31.98 g of a compound containing only carbon, hydrogen, and oxygen produces 62.47 g…

A: Given, Mass of Compound containing only carbon, hydrogen, and oxygen = 31.98 g Amount of CO2…

Q: You determine the empirical formula of a compound to be CH3. In a separate experiment, you determine…

Q: Determine the empirical formula of the compound according to its elemental analysis: 38.13% C by…

A: Determination of empirical formula The percentage composition of elements present in given compound…

Q: When 3.624 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 11.37 grams…

A: First, we will calculate mass percent of carbon and hydrogen in given hydrocarbon. Then emipirical…

Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

A 21.57 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 21.09 grams of CO0, and 4.317 grams of H20 are produced. In a separate experiment, the molar mass is found to be 90.04 g/mol. Determine the empirical formula and the molecular formula of the organic compound.
What is the molecular formula for a compound that has a molar mass of 92.0 g/mol and an empirical formula of NO2?
Vitamin c is known chemically by the name ascorbic acid. Determine the empirical formula of ascorbic acid if it is composed of 40.92% carbon, 4.58% hydrogen, and 54.50% oxygen.
A 21.57 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 21.09 grams of Co, and 4.317 grams of H20 are produced. In a separate experiment, the molar mass is found to be 90.04 g/mol. Determine the empirical formula and the molecular formula of the organic compound.
Calculate the number of moles of ethanol present in 243.3 mL of ethanol, CH3CH2OH, which has a density of 0.789 g/mL.
Combustion analysis of naphthalene, a hydrocarbon used in mothballs, produced 8.80 g CO2 and 1.44 g H2O. Calculate the empirical formula for naphthalene.
Combustion analysis of 2.400 g of an unknown compound containing carbon, hydrogen, and oxygen produced 4.171 g of CO2 and 2.268 g of H₂O. What is the empirical formula of the compound? The molar mass of CO₂ is 44.01 g mol-¹ and H₂O is 18.02 g mol-1. O C₂H1003 O C₂H5O2 O C3H8O2 O C₂H5O
When 6.608 grams of a hydrocarbon, C,Hy, were burned in a combustion analysis apparatus, 20.73 grams of CO2 and 8.489 grams of H,O were produced. In a separate experiment, the molar mass of the compound was found to be 70.13 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula molecular formula
Click in the answer box to activate the palette. Menthol is a flavoring agent extracted from peppermint oil. It contains C, H, and O. In one combustion analysis, 10.00 mg of the substance yields 11.53 mg H,0 and 28.16 mg CO2. What is the empirical formula of menthol? Add subscripts to complete the empirical formula. CHO
An organic compound is found to have an Empirical formula of C5H3O2 and a molecular weight (or molar mass) of 190.16 g/mole. What is the molecular formula for this compound? Choose three answers from the listed choices to report the molecular formula you have determined. H3 O2 O4 O6 C15 H9 C10 H6 C5
Determine the empirical formula of ascorbic acid if it is composed of 40.92% carbon, 4.58% hydrogen, and 54.50% oxygen. If the molar mass of the acid is 176.14 g/mole, calculate the molecular formula of the acid. Could you please show me the process of how to set it up.