The molar heat capacity of a diatomic molecule is 29.1 mol. Assuming the atmosphere contains only nitrogen gas and there is no heat loss, calculate the total heat intake (in kJ) if the atmosphere warms up by 3.0°C during the next 50 years. Given that there are 2.8 x 1020 moles of diatomic molecule present, how many kilograms of ice (at the North and South Poles) will this quantity of heat melt at 0° C? (The molar heat of fusion of ice is 6.01 kJ/mol.) Total heat intake: х 10 |kJ Ice melted: x 10 kg

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The molar heat capacity of a diatomic molecule is 29.1 J/K · mol. Assuming the atmosphere contains
only nitrogen gas and there is no heat loss, calculate the total heat intake (in kJ) if the atmosphere
warms up by 3.0°C during the next 50 years. Given that there are 2.8 x 10²20 moles of diatomic molecule
present, how many kilograms of ice (at the North and South Poles) will this quantity of heat melt at 0°
C? (The molar heat of fusion of ice is 6.01 kJ/mol.)
Total heat intake:
× 10
kJ
Ice melted:
× 10
|kg
(Enter your answer in scientific notation.)
Transcribed Image Text:The molar heat capacity of a diatomic molecule is 29.1 J/K · mol. Assuming the atmosphere contains only nitrogen gas and there is no heat loss, calculate the total heat intake (in kJ) if the atmosphere warms up by 3.0°C during the next 50 years. Given that there are 2.8 x 10²20 moles of diatomic molecule present, how many kilograms of ice (at the North and South Poles) will this quantity of heat melt at 0° C? (The molar heat of fusion of ice is 6.01 kJ/mol.) Total heat intake: × 10 kJ Ice melted: × 10 |kg (Enter your answer in scientific notation.)
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