The molar heat capacity at constant pressure for CO(g) is 6.97 cal mol-1 K-1. How much heat in cal is required to raise 0.62 g of CO(g) from 298 to 423K?   Atomic Mass: C: 12.011 g/mol O: 15.999 g/mol

Q: Sodium chloride, the table salt (NaCl) is added in cooking to enhance the flavor of the food.  When…

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Q: 3. 0.562 g of graphite is placed in a calorimeter with excess oxygen at 25.00 °C and 1 atm pressure.…

A: Mass of graphite = 0.562 g  Molar mass = 12.01 g/mol Moles of graphite = MassMolar mass=0.562 g12.01…

Q: How much heat is rel;eased to the surroundings when 5.00 g of CO2 is produced according to the…

A: We can solve the problem by determining the moles of CO2 that is actually produced in the reaction.…

Q: How much heat is absorbed in the comp eaction of 3.00 grams of SiO2 with ex arbon in the reaction…

A: Mole is equal to weight of substance divide by it's molar mass

Q: Determine

A: We will calculate ∆H rxn by doing operation in giving equation

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Q: 25.0 mL of 1.00 M HCl at 23.5oC react with 25.0 mL 1.00 M NaOH in a styrofoam calorimeter whose…

A: The energy of a system is always conserved. The amount of heat released or absorbed by the reaction…

Q: Excess sodium is reacted with 1.00 L of chlorine gas that has a density of 1.88 g/L to form sodium…

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Q: When 50.0 g of an aqueous solution of reagent 1 at 24.1oC is added to 100.0 g of of an aqueous…

A: Given : Mass of reagent 1 solution = 50.0 g Mass of reagent 2 solution = 100.0 g Initial temperature…

Q: How much heat, in joules, must be added to a 75.0 g block of a metal alloy with a specific heat of…

A: Given, Mass of the substance, m = 75.0 g Initial temperature, T1 = 25 oC Final temperature, T2 = 775…

Q: Consider the following reaction: 2C6H6() + 15 O2(g)- 12 CO2(g) + 6 H20() AH = -5.869 x 103 kJ An…

A: Each reaction takes place account to their stoichiometric radio and account to those things the heat…

Q: Under a constant pressure of 1.00 atm, at 25.00oC, the combustion of 1.136 g of C6H12O3(l) raises…

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Q: 0.015L of 3mol/L NaOH mixes in a calorimeter with 0.013L of 3mol/L HCl, the two initially at 295K,…

A: Given : Concentration of NaOH = 3.00 M Concentration of HCl = 3.00 M Volume of NaOH solution = 0.015…

Q: According to the following thermochemical equation, if 586.9 g O, is formed how much heat is…

A: Answer - According to the question - Given reaction  CO2 +(g) + 1/2H2O (l) ----- -> 1/2 C2H2 (g)…

Q: When 50.0 g of an aqueous solution of reagent 1 at 24.1oC is added to 100.0 g of of an aqueous…

A: Calorimetry is a chemical process in which we find out the heat transfer associated with the change…

Q: 25.0 mL of 1.00 M HCl at 23.5oC react with 25.0 mL 1.00 M NaOH in a styrofoam calorimeter whose…

A: Heat of neutralisation of an acid id defined as the amount of heat evolved when one equivalent of an…

Q: How much heat was absorbed by the solution?

A: For constant pressure calorimeter, we know that The heat absorbed by the calorimeter is given by…

Q: A sample of 0.552 g of metal x (molar mass= 113 g/mol) was reacted with 150 mL of 1.0 M HCl in a…

A: Given - mass of metal x = 0.552 g             Molar mass of metal x = 113 g/mol            Volume of…

Q: 150 ml of .350M HCl was mixed with 150 mL of .350 M NaOH in a calorimeter of negligible heat…

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Q: etermine the enthalpy for the reaction shown below. CS2(l)  +  3O2(g)  -->  CO2(g)  +  2SO2(g)…

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Q: A 1.00 g sample of MgCl2 produced a 10.00 °C increased in a calorimeter charged with 40.0mL of…

A: Mass of MgCl2 = 1.00 g Increase in temperature, ΔT = 10.00 °C Specific heat of MgCl2, C = 0.750…

Q: A metal pellet with mass 25.0 g and temperature 90.0 °C is dropped into 100.0 g water originally at…

A: Given:  Mass of metal = 25.0 gm  Initial  temperature = 90.0 °C  Mass of water = 100 gm  Initial…

Q: reagents inside a simple calorimeter. The outside of the calorimeter is made of an aluminum cup with…

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Q: Determine the enthalpy for the reaction shown below. CS2(l)  +  3O2(g)  -->  CO2(g)  +  2SO2(g)…

A: In this question, we have to find out the correct answer of given problem by the help of…