The MINITAB analysis uses the pooled estimate of a?. Is the assumption of equal variances reasonable? Why or why not? (Round your answer to three decimal places.) The ratio of the larger of the two sample variances to the smaller is which is less than than 3, so the assumption of equal variances is reasonable.

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Question
100%

solve for part c

Data on the estimated average price for a variety of different brands of tuna, based on prices paid nationally in supermarkets, are shown in the following table. Use the MINITAB printout to answer the questions in parts (a)-(c). (Use the exact values found in the
MINITAB output.)
Light Tuna
in Water
Light Tuna
in Oil
1.01
0.51
2.54
0.60
1.94
1.43
1.90
0.64
1.25
1.10
1.32
0.64
0.87
0.65
1.77
0.67
0.67
0.69
1.21
0.62
0.67
0.62
0.69
0.62
0.68
Two-Sample T-Test and CI: Light Water, Light Oil
Descriptive Statistics
Sample
N
Mean
StDev
SE Mean
Light Water
14
0.908
0.403
0.11
Light Oil
11
1.145
0.668
0.20
Estimation for Difference
95% CI for
Difference
Pooled StDev
difference
-0.238
0.534
(-0.683, 0.208)
Test
H: H1 - H2 = 0
H: H - H2 # o
Null hypothesis
Alternative hypothesiS
T-Value
DF
P-Value
-1.10
23
0.281
Transcribed Image Text:Data on the estimated average price for a variety of different brands of tuna, based on prices paid nationally in supermarkets, are shown in the following table. Use the MINITAB printout to answer the questions in parts (a)-(c). (Use the exact values found in the MINITAB output.) Light Tuna in Water Light Tuna in Oil 1.01 0.51 2.54 0.60 1.94 1.43 1.90 0.64 1.25 1.10 1.32 0.64 0.87 0.65 1.77 0.67 0.67 0.69 1.21 0.62 0.67 0.62 0.69 0.62 0.68 Two-Sample T-Test and CI: Light Water, Light Oil Descriptive Statistics Sample N Mean StDev SE Mean Light Water 14 0.908 0.403 0.11 Light Oil 11 1.145 0.668 0.20 Estimation for Difference 95% CI for Difference Pooled StDev difference -0.238 0.534 (-0.683, 0.208) Test H: H1 - H2 = 0 H: H - H2 # o Null hypothesis Alternative hypothesiS T-Value DF P-Value -1.10 23 0.281
O H, is not rejected. There is insufficient evidence to conclude that there is a difference in the average prices of light tuna in water versus oil.
(b) What is the p-value for the test?
p-value = 0.281
(c) The MINITAB analysis uses the pooled estimate of o?. Is the assumption of equal variances reasonable? Why or why not? (Round your answer to three decimal places.)
The ratio of the larger of the two sample variances to the smaller is
which is less than
V than 3, so the assumption of equal variances is
reasonable.
Transcribed Image Text:O H, is not rejected. There is insufficient evidence to conclude that there is a difference in the average prices of light tuna in water versus oil. (b) What is the p-value for the test? p-value = 0.281 (c) The MINITAB analysis uses the pooled estimate of o?. Is the assumption of equal variances reasonable? Why or why not? (Round your answer to three decimal places.) The ratio of the larger of the two sample variances to the smaller is which is less than V than 3, so the assumption of equal variances is reasonable.
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