The melting temperature of TNT (2,4,6-trinitrotoluene) is 80.83 °C, and its enthalpy change of fusion is 21.23 kJ mol¹. Assume that TNT forms an ideal liquid solution with nitrobenzene. Find the maximum solubility at 79.70 °C and 58.70 °C. This is equivalent to finding the mole fractions of TNT and nitrobenzene at those temperatures. Assume that the liquid solution is ideal and that no solid solubility occurs.

The melting temperature of TNT (2,4,6-trinitrotoluene) is 80.83 °C, and its enthalpy change of fusion is 21.23 kJ mol¹. Assume that TNT forms an ideal liquid solution with nitrobenzene. Find the maximum solubility at 79.70 °C and 58.70 °C. This is equivalent to finding the mole fractions of TNT and nitrobenzene at those temperatures. Assume that the liquid solution is ideal and that no solid solubility occurs.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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