The mean weight of shipping containers is supposed to be no more than 11.7 kg. To test whether or not this value has since increased, a random sample of size 290 containers are weighed and found to have a sample mean of 12.1 kg. We will assume that the population of container weights is normally distributed with standard deviation of 3.7 kg. Test whether the mean population weight has increased at a level of significance of 0.5%. Show your relevant steps below. Step 1: Hypotheses: • The null hypothesis Ho is (choose one): H = 3.7 µ = 290.0 For the alternative hypothesis Ha we change the equal sign in Ho to (choose one): µ = 11.7 O Hu = 12.1 Step 2: Rejection Region: The rejection region is bounded by the following critical values:

MATLAB: An Introduction with Applications
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The mean weight of shipping containers is
supposed to be no more than 11.7 kg. To test
whether or not this value has since increased, a
random sample of size 290 containers are
weighed and found to have a sample mean of
12.1 kg.
We will assume that the population of container
weights is normally distributed with standard
deviation of 3.7 kg.
Test whether the mean population weight has
increased at a level of significance of 0.5%. Show
your relevant steps below.
Step 1: Hypotheses:
• The null hypothesis Ho is (choose one):
µ = 3.7 OH = 11.7 OH = 12.1
%D1
u = 290.0
• For the alternative hypothesis Ha we change
the equal sign in Ho to (choose one):
Step 2: Rejection Region:
The rejection region is bounded by the following
critical values:
Critical z valuee
Transcribed Image Text:The mean weight of shipping containers is supposed to be no more than 11.7 kg. To test whether or not this value has since increased, a random sample of size 290 containers are weighed and found to have a sample mean of 12.1 kg. We will assume that the population of container weights is normally distributed with standard deviation of 3.7 kg. Test whether the mean population weight has increased at a level of significance of 0.5%. Show your relevant steps below. Step 1: Hypotheses: • The null hypothesis Ho is (choose one): µ = 3.7 OH = 11.7 OH = 12.1 %D1 u = 290.0 • For the alternative hypothesis Ha we change the equal sign in Ho to (choose one): Step 2: Rejection Region: The rejection region is bounded by the following critical values: Critical z valuee
Step 2: Rejection Region:
The rejection region is bounded by the following
critical values:
Critical z value(s)
(Enter critical values from lowest to highest.
Leave second blank empty if there is only one
critical value.)
Step 3: Test Statistic:
Standard Error =
Calculated test statistic, z =
(Keep at least five significant figures for all
calculated intermediate values.)
Step 4: Decision on HO:
At a level of significance of 0.5% (choose one):
Reject Ho and accept Ha
Fail to reject Ho
Transcribed Image Text:Step 2: Rejection Region: The rejection region is bounded by the following critical values: Critical z value(s) (Enter critical values from lowest to highest. Leave second blank empty if there is only one critical value.) Step 3: Test Statistic: Standard Error = Calculated test statistic, z = (Keep at least five significant figures for all calculated intermediate values.) Step 4: Decision on HO: At a level of significance of 0.5% (choose one): Reject Ho and accept Ha Fail to reject Ho
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